Precipitation is the formation of an insoluble substance. For the equation
AB(s)⇌A+(aq)+B−(aq),
precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to decrease the concentrations of A+ and B−. This critical level, Ksp, is a constant at a certain temperature. In this case,
Q=[A+][B−],
where Q is the ion product.When Q>Ksp, precipitation occurs until Q is equal to Ksp.
When Q≤Ksp, a precipitate does not form.
Question:
a) What is the value of Q when the solution contains 2.50×10−3M Mg2+ and 2.00×10−3M CO32−?
b) What concentration of the lead ion, Pb2+, must be exceeded to precipitate PbBr2 from a solution that is 1.00×10−2 M in the bromide ion, Br−? Ksp for lead(II) bromide is 4.67×10−6 .

Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not. Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to...
Learning Goal: To understand the relationship between precipitation and the solubility product and to be able to predict whether a substance will precipitate or not. Precipitation is the formation of an insoluble substance. For the equation AB(s)⇌A+(aq)+B−(aq), precipitation represents a shift to the left and the production of a solid. From Le Châtelier's principle, we know that when the product of the concentrations of A+ and B− gets above a certain level, the reaction will respond by shifting left to...
What is the value of Q when the solution contains 2.50×10-3M Mg2+ and 2.00×10-3M CO32-?What concentration of the lead ion, Pb2+ , must be exceeded to precipitate PbF2 from a solution that is 1.00×10-2 M in the fluoride ion, F- Ksp for lead(II) fluoride is 3.3×10-8.
Determine whether a precipitate form in the following reaction conditions: a. A solution containing lead (II) nitrate is mixed with one containing sodium bromide to form a solution that is 0.0150 M in Pb(NO3)2 and 0.00350 M in NaBr. Does a precipitate form in the newly mixed solution? Ksp PbBr2 = 4.67 x 10-6 . b. A solution containing iron (II) nitrate is mixed with one containing sodium phosphate to form a solution that is 0.0365 M in Fe(NO3)2 and...
Predict Precipitation Question Consider the following equilibrium: Ag, PO, (s) 3 Ag (aq) + PO(aq) If the concentration of the Ag ion at a certain point is 6.3 x 10 M, and Ksp=9.1 x 104, will a precipitate form? - Select the correct answer below: Oyes, because Q> K yes, because Q < K no, because o> K no, because < K
Predict Precipitation Question Consider the following equilibrium: Ag, PO, (s) 3 Ag (aq) + PO(aq) If the concentration...
1) For the reaction: PbCl2(s) ↔ Pb2+(aq)+2Cl1-(aq), what is Q* when 2.5 mL of 0.070 M lead nitrate is added to 19 mL of 0.018 M sodium chloride? Ksp of lead chloride is 1.6 x 10-5 M3. Hint given in general feedback *Recall: Q is compared to Ksp to determine whether a precipitate forms. 2) Sodium phosphate is added to a solution that contains 0.0041 M aluminum nitrate and 0.028 M calcium chloride. The concentration of the first ion to...
Lead (II) bromide dissociates according to the following equation PbBr2 (s) ↔ Pb2+ + 2 Br- Determine the value of Q, the reaction quotient based (also known as the ion product) for a solution with the concentrations below. (Pb2+) = 0.0048 M, (Br-) = 0.0028 M
Consider the following equilibrium: PbI2(s)↽−−⇀Pb2+(aq)+2I−(aq) If the concentration of the Pb2+ ion at a certain point is 2.1×10−3 M, and Ksp=7.5×10−11, will a precipitate form? Select the correct answer below: yes, because Q>Ksp yes, because QKsp no, because Q
Lead (II) bromide dissociates according to the following equation PbBr2 (s) ↔ Pb2+ + 2 Br- Determine the value of Q, the reaction quotient based (also known as the ion product) for a solution with the concentrations below. (Pb2+) = 0.0018 M, (Br-) = 0.0044 M Report your answer in scientific notation with two significant figures. For example 1.2x10-5 would be entered as 1.2e-5
Lead (II) bromide dissociates according to the following equation PbBr2 (s) ↔ Pb2+ + 2 Br- Determine the value of Q, the reaction quotient based (also known as the ion product) for a solution with the concentrations below. (Pb2+) = 0.0017 M, (Br-) = 0.0016 M Report your answer in scientific notation with two significant figures. For example 1.2x10-5 would be entered as 1.2e-5