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Light rays in a material with index of refrection 1.33 can undergo total internal reflection when they strike the interface w

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Answer #1

Here,

let the refractive index of second material is n

Using Snell's law for total internal reflection

1.33 * sin(71.5) = n * sin(90 degree)

n = 1.26

the material's refractive index is 1.26

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