![II Review | Constants | Periodic Table Part G For 4.8 x 10-4 M Ca(OH)2, determine [OH-] and [H3O+]. Express your answers in m](http://img.homeworklib.com/questions/0e9f4f00-7150-11ea-8b29-05aaba76cf35.png?x-oss-process=image/resize,w_560)
Homework Answers
1 Molecule of Ca(OH)2 has 2 OH-
So,
[OH-] = 2*[Ca(OH)2]
= 2*4.8*10^-4 M
= 9.6*10^-4 M
use:
[H3O+] = Kw/[OH-]
Kw is dissociation constant of water whose value is 1.0*10^-14 at 25 oC
[H3O+] = (1.0*10^-14)/[OH-]
[H3O+] = (1.0*10^-14)/9.6*10^-4
[H3O+] = 1.0*10^-11 M
Answer:
9.6*10^-4 , 1.0*10^-11
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