Question

For each of the following strong base solutions, determine [OH−][OH−] and [H3O+][H3O+] and pHpH and pOHpOH.

1.) For 8.73×10−38.73×10−3 MM LiOHLiOH, determine [OH−][OH−] and [H3O+][H3O+].

Express your answers in moles per liter to three significant figures separated by a comma.

2.) For 1.10×10−21.10×10−2 MM Ba(OH)2Ba(OH)2, determine [OH−][OH−] and [H3O+][H3O+].

Express your answers in moles per liter to three significant figures separated by a comma.

3.) For 2.1×10−42.1×10−4 MM KOHKOH, determine [OH−][OH−] and [H3O+][H3O+].

Express your answers in moles per liter to two significant figures separated by a comma.

4.) For 5.0×10−45.0×10−4 MM Ca(OH)2Ca(OH)2, determine [OH−][OH−] and [H3O+][H3O+].

Express your answers in moles per liter to two significant figures separated by a comma.

PLEASE HELP!

Answer 1

Please go w attached images for all answers
» & D in aqueous solution [4+1 [or] = 154m² at 25°c Ht exist in form of [to+] in aqueous solution 8.73 x16 PM LiOH -, stoong Base Ionises completely LiOH - Lit + oH mol L 1.14 [OH) = concentration of LiOH = 8.73x10-3M = 8.73x10-3 moll since," [ht] [ot] = 1514 m2 [#1] = 1014 m2 8. 73 x 103 m [**] = 1.14 x 10- 10 M 1.10X10-2M BacoH), - Stoong Base — Ba(OH)₂ Bate + 2017 [on] = 2 x Ba(OH)₂ concentration = ax 1.10X162 M = 2.20*102 M - 10-14 m² . 2.20x162 m = 4.54 x 1011 Iorises completely

Base - Sonises completely * 2.40X174M KOH — Stoong KOH K t + oH Tor] = concentration of koh = 2.10x10m 14t) = 1074 m² = 4.76x109 m 2. 10x154M 6 5.00x104m ca Cot Strong Base Calon) - Cat2 + 200 Lor]= 2x conc. of calon = ax 5.00010 4 M = 1.00 x103 (H) = 1014 m2 1.00×103m = 1.00x10" M.