Question

Find the equivalent capacitance of the group of capacitors shown in the figure below. (Let C₁ = 4.90 μF, C₂ = 4.20 μF, C₃ = 2.80 μF, C₄ = 1.90 μF, C₅ = 2.80 μF, C₆ = 7.50 μF, C₇ = 5.70 μF.)

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Safari File Edit View History Bookmarks Window Help 50% D' El Mon 3:08:36 PM a Submit Answer Save Progress Practice Another Version 2. 0/10 points I Previous Answers sercp11 16.a.p.065.nva My Notes Ask Your Teacher Find the equivalent capacitance of the group of capacitors shown in the figure below (Let C1 = 4.90μF C2 = 4.20 μF· C3 = 2.80 μΕ C-1.90μF. C5 = 2 80 0.724 Your response differs from the correct answer by more than 10%. Double check your calculations. Ci Cs C2 Cs 48.0 V 3. 0/10 pointsI Previous Answers sercp11 17.2 p.003.nva My Notes Ask Your Teacher

Answer 1

capacitance of upper wire

Ca = [ C3^-1 + ( C1 + C2)^-1] ^-1

Ca = [ 2.8^-1 + ( 4.2 + 4.9)^-1 ^-1

Ca = 2.14 uF

calacitance of middle wire

Cb = [ 5.7^-1 + ( 1.9 + 2.8+ 7.5)^-1] ^-1

Cb = 3.88 uF

net capacitance = Ca + Cb = 6.02 uF

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