Question

Find the equivalent capacitance of the group of capacitors shown in the figure below. (Let C1 = 4.60 µF, C2 = 3.80 µF, C3 = 3.10 µF, C4 = 2.20 µF, C5 = 2.70 µF, C6 = 7.20 µF, C7 = 6.10 µF.) A circuit is made up of two rectangular loops, one on top of the other. The bottom side of the lower loop contains a 48.0 V battery, where its positive terminal is to the left of its negative terminal. The top side of the lower loop, which is also the bottom side of the upper loop, contains a capacitor C7, then splits into three parallel horizontal branches before recombining and continuing to the end of the side. Each branch contains one capacitor. From top to bottom, they are C4, C5, and C6. The top side of the top loop splits into two parallel horizontal branches before recombining and continuing to a capacitor C3. Each branch contains one capacitor. From top to bottom, they are C1 and C2. µF

Answer 1

Circuit Diagram.

calculating capacitance of capacitors connected in parallel.