Question

Find the charge on each of the capacitors in the figure below. A rectangular circuit contains a battery and four capacitors. A 24.0 V battery is on its left side, where the positive terminal is above the negative terminal. Its right side splits into two parallel vertical branches below the top right corner of the circuit, where there is a 1.00 µF capacitor on the left branch and a 5.00 µF capacitor on the right branch. The branches recombine, the side continues down, and then splits again into two parallel vertical branches. There is an 8.00 µF capacitor on the left branch and a 4.00 µF capacitor on the right branch. These branches then recombine and the side continues down to reach the bottom right corner of the circuit.

Find the charge on each of the capacitors in the figure below 1.00 μ.F 24.0 V 8.00 μF 4.00 μF 1.0μF capacitor 5.0-μF capacitor 8.0-μF capacitor 4.0μF capacitor με

Answer 1

" Parallel C' = 1 + 5 = 6 mu F Parallel C"" = 8 + 4 = 12 mu F Series C_eq = 6 times 12/6 + 12 = 4 mu F Q = C_eq V = 4 times 10^-6 times 24 = 96 mu C V' = Q/C' = 96 times 10^-6/6 times 10^-6 = 16V V"" = Q/C"" = 96 times 10^-6/12 times 10^-6 = 8V 1.0 mu F: Q_1 mu F = 1 times 10^-6 times 16 = 16 mu C 5.0 mu F: Q_5 mu F = 5 times 10^-6 times 16 = 80 mu C 8.0 mu F: Q_8 mu F = 8 times 10^-6 times 8 = 64 mu C 4.0 mu F: Q_4 mu F = 4 times 10^-6 times 8 = 32 mu C"