CH4(g) + 2O2(g) ---------> CO2(g) +
2H2O(l)
H = -890.4KJ --------------> 1
C (s) + O2(g) ------------->
CO2(g)
H = -393.5Kj ---------------->2
2C(s) + O2(g) ---------->
2CO(g)
H = -221.0KJ ------------> 3
adding equation 2 and 3
C (s) + O2(g) ------------->
CO2(g)
H = -393.5Kj ---------------->2
2C(s) + O2(g) ---------->
2CO(g)
H = -221.0KJ ------------> 3
---------------------------------------------------------------------------------------------------------------
3C(s) + 2O2(g) ------------> CO2(g) +
2CO(g)
H =- 614.5Kj ----------------> 5
subtract equation 5 and 1
3C(s) + 2O2(g) ------------> CO2(g) +
2CO(g)
H =- 614.5Kj ----------------> 5
CH4(g) + 2O2(g) ---------> CO2(g) +
2H2O(l)
H = -890.4KJ --------------> 1
(-) (-) (-) (-) (+)
-------------------------------------------------------------------------------------------------------------
3C(s) + 2H2O(l) ------------> CH4(g) +
2CO(g)
H = 275.9KJ >>>>>answer
Consider following chemical reactions: 1) CH2(g) + 2O2(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g)...
please help
Consider following chemical reactions: 1) CH.(g) + 2O2(g) → CO2(g) + 2H2O(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) - 200(g) 4) 3C(s) + 2H2O) CH4(g) + 2COg) H2O(l) indicates that H20 is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and - 221.Okj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Consider following chemical reactions: 1) CH2(g) + 202(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) → 2C0(9) 4) 3C(s) + 2H2O(l) → CH4(g) + 2CO(g) H2O(l) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Consider following chemical reactions: 1) CHa(g) +202(8)-CO2(g) 2H20() 2) C(s) O2(g) CO2(g) 3) 2C(s)O2(g) 2CO(g) 4) 3C(s) 2H20()CH4(g)2CO(g) H2O(I) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Calculate ΔrH for the following reaction: CH4(g)+2O2(g)→CO2(g)+2H2O(l) Use the following reactions and given ΔrH's. CH4(g)+O2(g)→CH2O(g)+H2O(g), ΔrH = -284 kJmol−1 CH2O(g)+O2(g)→CO2(g)+H2O(g), ΔrH = -527 kJmol−1 H2O(l)→H2O(g), ΔrH = 44.0 kJmol−1
Use the example shown to calculate the reaction enthalpy, delta H, for the following reaction: CH4(g)+2O2(g)->CO2(g)2H2O(l). Use the series of reaction that follows: 1. C(s)+2H2(g)-> CH4(g), delta H= -74.8 kJ 2. C(s)+O2(g)->CO2(g), delta H= -393.5 kJ 3. 2H2(g)+O2(g)-> 2H2O(g), delta H= -484.0 kJ 4. H2O(l)->H2O(g), delta H= 44.0 kJ
CH4(g) + 2O2(g) CO2(g) + 2H2O(l) ΔHo = -890.5 kJ. What would be the ΔHo for the reaction ½ CH4(g) + O2(g) ½ CO2(g) + H2O(l) What would be the ΔHo for the reaction ½ CH4(g) + O2(g) ½ CO2(g) + H2O(l) What would be the ΔHo for ½ CO2(g) + H2O(l) ½ CH4(g) + O2(g)
The equilibrium constant expression K c for the reaction CH4 (g) + 2O2 (g) <--> CO2 (g) + 2H2O (g) is __________. A. Kc = [CO2][H2O]/[CH4][O2] B. Kc = [CO2][H2O]2/[CH4][O2]2 C. Kc = [CH4][O2]/[CO2][H2O] D. Kc = [CH4][O2]2/[CO2][H2O]2
What is the enthalpy change for the first reaction? CH4(g) + 1/2O2(g) → CH3OH(g) ΔH = CH4(g) + 2O2(g) → CO2(g) + 2H2O(g) ΔH = -802.4 CH3OH(l) + 3/2 O2 → CO2(g) + 2H2O(g) ΔH = -678.1
Calculate the enthalpy of the following reaction: C (s) + 2 H2 (g) --> CH4 (g) Given: C (s) + O2 (g) --> CO2 ΔH = -393 kJ H2 + 1⁄2O2 --> H2O. ΔH = -286 kJ CH4 + 2O2 --> CO2 + 2H2O ΔH = -892 kJ
Consider the four reactions listed below for the next question. 1. FeO(s)+CO(g)<->Fe(s)+Co2(g) K=0.403 2. 2C(s)+O2(g)<->2CO(g) K=1x10at16 power 3. 2Cl2(g)+2H2O(l)<->4HCl(aq)+O2(g) K=1.9x10 at-15 power 4. C(s)+2H2(g)<->CH4(g) K=27.5 a.Which reaction has the smallest tendency to occur? 1. Reaction a 2. Reaction b 3. Reaction c 4. Reaction d