Lets number the reaction as 1, 2, 3, 4 from top to bottom
required reaction should be written in terms of other reaction
This is Hess Law
required reaction can be written as:
reaction 4 = -1 * (reaction 1) +1 * (reaction 2) +1 * (reaction 3)
So, ΔHo rxn for required reaction will be:
ΔHo rxn = -1 * ΔHo rxn(reaction 1) +1 * ΔHo rxn(reaction 2) +1 * ΔHo rxn(reaction 3)
= -1 * (-890.4) +1 * (-393.5) +1 * (-221.0)
= 275.9 KJ
Answer: 275.9 KJ
Consider following chemical reactions: 1) CHa(g) +202(8)-CO2(g) 2H20() 2) C(s) O2(g) CO2(g) 3) 2C(s)O2(g) 2CO(g) 4) 3C(...
Consider following chemical reactions: 1) CH2(g) + 202(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) → 2C0(9) 4) 3C(s) + 2H2O(l) → CH4(g) + 2CO(g) H2O(l) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.0kj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
Consider following chemical reactions: 1) CH2(g) + 2O2(g) → CO2(g) + 2H20(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) 200(g) 4) 3C(s) + 2H2O(l) → CH4(9) + CO2(g) H2O(l) indicates that H2O is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and -221.Okj respectively, try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
please help
Consider following chemical reactions: 1) CH.(g) + 2O2(g) → CO2(g) + 2H2O(1) 2) C(s) + O2(g) → CO2(g) 3) 2C(s) + O2(g) - 200(g) 4) 3C(s) + 2H2O) CH4(g) + 2COg) H2O(l) indicates that H20 is in liquid state. If the Enthalpy of reaction for reaction 1, 2, and 3 are -890.4kj, -393.5kj and - 221.Okj respectively; try to figure out the Enthalpy of reaction for reaction 4. Please show your work.
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