An electron is traveling through a region of space in which the electric field is along the +x direction and has a magnitude of 1922 N/C. What is the acceleration of the electron?
| magnitude | m/s2 |
| direction |
Solution,
Force, F = qE = ma
Acceleration, a = qE/m = (1.6 x 10^-19 x 1922)/(9.1 x 10^-31)
Acceleration, a = 3.38 x 10^14 m/s^2
Comment in case any doubt please rate my answer ....
An electron is traveling through a region of space in which the electric field is along...
An electron is traveling through a region of space in which the
electric field is along the +x direction and has a
magnitude of 1652 N/C. What is the acceleration of the
electron?
magnitude direction x m/s2
An electron traveling horizontally enters a region where a uniform electric field of 15 N/C is directed upward. What is the magnitude and direction of the force exerted on the electron once it has entered the field?
A charged particle moves along the x-axis through a region with a uniform magnetic field that is oriented to lie in the x-y plane. Part a) Assume that the particle has a net charge of +669 μC and is moving with a velocity of 464 m/s in the +x direction at a particular instant. In that region of space, there is a uniform magnetic field of 1.91T directed in the x-y plane at an angle of +29.8 ∘ relative to...
In a region of space there is an electric field E~ that is in the z-direction and that has magnitude E=(868N/(C?m))x. Find the flux for this field through a square in the xy-plane at z = 0 and with side length 0.330 m. One side of the square is along the +x -axis and another side is along the +y-axis. [answer is 15.6 N.m2/C] please explain and show work thanks!
ConstantsI Periodic Table Part A An electron is traveling through a uniform electric field. The field is constant and given by B-(2.00 x 10-11 N/C) ^-(1.20 x 10-11 N/C) j At t 0, the electron is at the origin and traveling in the x direction with a speed of 2.10 m/s What is its position 2.10 s later? Submit Request Answer Part B im Submit Request Answer
The net electric field in a region of space is a vector sum of two parts. The first has a magnitude of E1 = 1100 N/C and points at an angle of 25° from the positive x axis towards the positive y axis. The second has a magnitude of E2 = 1600 N/C and points 50° from the positive y axis towards the negative x axis. A 5.0 kg mass, that is charged to 0.10 C, is moving at 10...
An electron moves at 3.00×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.90×10−2 T . a- What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? b- What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field? c- If the actual acceleration of the electron is 14 of the largest magnitude in part (a), what is the...
An electron moves at 2.60×106 m/s through a region in which there is a magnetic field of unspecified direction and magnitude 7.00×10−2 T . Part A What is the largest possible magnitude of the acceleration of the electron due to the magnetic field? Part B What is the smallest possible magnitude of the acceleration of the electron due to the magnetic field? Part C If the actual acceleration of the electron is 14 of the largest magnitude in part (a),...
An electron is traveling in the positive x direction. A uniform electric field is present and oriented in the negative z direction. If a uniform magnetic field with the appropriate magnitude and direction is simultaneously generated in the region of interest, the net force on the electron can be made to have a magnitude of zero. What must the direction of the magnetic field be?
An electron traveling left to right enters a region of space where a uniform magnetic field exists (see figure). Once in the field, the electron follows a circular path where r = 1.0E-6 m. If the magnitude of the magnetic field is 5.5 T, what is the speed of the electron and the direction of the magnetic field? 530 m/s, into the screen 530 m/s, out of the screen 9.7E5 m/s, into the screen 9.7E5 m/s, out of the screen...