Question

A lift is moving upward with an acceleration a=0.5ms2. There is a block of mass m-16 kg on the floor of the lift. What is the

0 0
Add a comment Improve this question Transcribed image text
Answer #1

Solution:

Given:

Acceleration (a) = 0.5 m/s2

And, m = 16 kg

Here, Contact force (F) can be given as :

F = m a + m g = m (a + g) = (16 kg){(0.5 m/s2) + (9.8 m/s2)} = 164.8 N

Add a comment
Know the answer?
Add Answer to:
A lift is moving upward with an acceleration a=0.5ms2. There is a block of mass m-16...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • A box of mass m=46.6kg is pushed upward with an acceleration a=7.7ms 2 by a horizontal...

    A box of mass m=46.6kg is pushed upward with an acceleration a=7.7ms 2 by a horizontal force F. The slope on which the box rests makes an angle a=55 degree. What should be the force F? Refer to the figure below. The unit of the answer is N. Q3.4 Aceleraton a g=9.8ms 2 Force F Mass m

  • (a) An elevator of mass m moving upward has two forces acting on it: the upward...

    (a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? Tw    Both forces are equal. (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? Tw    Both forces are equal. (c) When the elevator is moving upward, but the acceleration is downward, which is...

  • (a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the d...

    (a) An elevator of mass m moving upward has two forces acting on it: the upward force of tension in the cable and the downward force due to gravity. When the elevator is accelerating upward, which is greater, T or w? T w Both forces are equal. (b) When the elevator is moving at a constant velocity upward, which is greater, T or w? T w Both forces are equal. (c) When the elevator is moving upward, but the acceleration...

  • The figure below shows an initially stationary block of mass m on a floor. A force...

    The figure below shows an initially stationary block of mass m on a floor. A force of magnitude F = 0.520·mg is then applied at upward angle ? = 16°. (a) What is the magnitude of the acceleration of the block across the floor if (a) µs = 0.600 and µk = 0.500? m/s2 (b) What is the magnitude of the acceleration of the block across the floor if µs = 0.400 and µk = 0.300? m/s2

  • 3. A block of mass m = 6.2 kg, moving on a frictionless surface with a...

    3. A block of mass m = 6.2 kg, moving on a frictionless surface with a velocity of -6.5 m/s to the right, collides with a block of mass M at rest, as shown in the figure. After the collision, the 6.2-Kg block recoils with a velocity of f =0.70 m/s to the left. If the blocks are in contact for 0.30 s, what is the magnitude of the average force on the 6.2-kg block, while the two blocks are...

  • Consider the block arrangement for the following situations: (a) Block moving upward at constant speed (b) Block moving...

    Consider the block arrangement for the following situations: (a) Block moving upward at constant speed (b) Block moving downward at constant speed (c) Block moving upward, speed decreasing (d) Block moving upward, speed increasing (e) Block stationary it was like that i dont understand the question. help. Example 5.2.1 Sample Problem Block accelerating vertically This first figure shows a vertically moving block on the end of a cord. Example 5.2.1 Figure 1 This second figure gives the vertical velocity component...

  • A block of mass m lies on a horizontal table. The coefficient of static friction between...

    A block of mass m lies on a horizontal table. The coefficient of static friction between the block and the table is ?s. The coefficient of kinetic friction is ?k, with ?k<?s. 1)If the block is at rest (and the only forces acting on the block are the force due to gravity and the normal force from the table), what is the magnitude of the force due to friction? 2)Suppose you want to move the block, but you want to...

  • A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a...

    A block of mass m = 8.40 kg, moving on a horizontal frictionless surface with a speed 4.20 m/s, makes a perfectly elastic collision with a block of mass M at rest. After the collision, the 8.40 kg block recoils with a speed of 0.400 m/s. In the figure, the blocks are in contact for 0.200 s. What is the magnitude of the average force on the 8.40 kg block, while the two blocks are in contact?

  • To understand kinetic and static friction. A block of mass m lies on a horizontal table. The coefficient of static fric...

    To understand kinetic and static friction. A block of mass m lies on a horizontal table. The coefficient of static friction between the block and the table is μs. The coefficient of kinetic friction is μk, with μk<μs. a- Suppose you want to move the block, but you want to push it with the least force possible to get it moving. With what force F must you be pushing the block just before the block begins to move? Express the...

  • A block of mass m= 81 kg slides down a vertical plane, where the normal force...

    A block of mass m= 81 kg slides down a vertical plane, where the normal force between the vertical plane and the block is non-zero. If the magnitude of acceleration of the block is a =2.5 m/s², find the force of friction between the block and the plane in units of N (Newton). Take g=9.8 m/s2

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT