Question

016 (part 1 of 3) 10.0 points An air-filled capacitor consists of two parallel plates, each with an area of 4.65 cm, sepa- rated by a distance of 1.66 mm. A 17.7 V potential difference is applied to these plates. Find the magnitude of the electric field be- tween the plates. The permittivity of free space is 8.8542 x 10 12 c /N-m2 Answer in units of kV/m. 017 (part 2 of 3) 10.0 points Find the capacitance. Answer in units of pF. 018 (part 3 of 3) 10.0 points Find the magnitude of the charge on each plate. Answer in units of pC.

Answer 1

Electric field (E) = sigma_epsilon_0 implies Q/ A epsilon_0 sigma = surface charge density sigma Q/ A Q = cv c = capacitance c = epsilon_0 A/ alpha = 8.85 times 10^-12 times 4.65 times 10^-4/ 1.66 times 10^-3 = 24.79 times 01^-13 F c = 2.48 times 01^-12F Q = 2.48 times 01^-12 times 17.7 q = 43.9 times 01^-12 c E = 43.9 times 10^-12/ 4.65 times 10^-4 times 8.85 times 10-12 E = 10.7 times 01^3 N/C