Question

A 10.6 kV/m electric field is used to inject a sample onto a 66.4 cm long capillary that has a diameter of 50 μm. The sample has an apparent mobility of 5.32×10−8 m2/(V⋅s) and a conductivity that is 1/15 of the conductivity of the buffer. How long must the electric field be applied to inject a sample that is 2.19% of the length of the capillary?

Answer 1

Given that, È = 10.6 kv/m I = 66.4 cm 4 = 5.32x10-8 m²/v-s Now you calculate v X 10.6 X 109 = 5.32 x108 m?/ vos = 56.39 xlos mis you calculate the Now di 2-19 % of 66.4 cm d = 2.19 x 100 66.4 *100 Now = 3.30 cm you calculate time d - 3.30x 10-2 t = 56.39 x lossi = 0.0585 * 403s t = 58.5 second