| 1 | |||||||
| Using the present value tables and assuming payment is made at end of the period we can calculate the annual payments | |||||||
| Annual payment | Loan amount/Present value factor of ordinary annuity (i=10%,n=4) | ||||||
| Present value | $150,000 | ||||||
| n= | 4 | ||||||
| i= | 10% | ||||||
| Annual installment | $47,321 | 150000/3.16987 | |||||
| 2 | |||||||
| Annual payment | Loan amount/Present value factor of ordinary annuity (i=10%,n=4) | ||||||
| Present value | $150,000 | ||||||
| n= | 5 | ||||||
| i= | 8% | ||||||
| Annual installment | $37,568 | 150000/3.99271 | |||||
| 3 | |||||||
| Annual payment | Loan amount/Present value factor of ordinary annuity (i=10%,n=4) | ||||||
| Present value | $150,000 | ||||||
| n= | 8 | ||||||
| i= | 10% | ||||||
| Annual installment | $28,117 | ||||||
| Present value of annuity | 150000/28117 | ||||||
| Present value of annuity | 5.33485 | ||||||
| Using the present value of annuity table and i=10% we get approx 8 years | |||||||
| 4 | |||||||
| Annual payment | Loan amount/Present value factor of ordinary annuity (i=10%,n=4) | ||||||
| Present value | $150,000 | ||||||
| n= | 3 | ||||||
| i= | 7% | ||||||
| Annual installment | $57,158 | ||||||
| Present value of annuity | 150000/57158 | ||||||
| Present value of annuity | 2.62430 | ||||||
| Using the present value of annuity table and in n column of 3 we get 2.62430 in case of i=7% | |||||||
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV= $1 (1 + ir n/i 5.5% 1 1.01000 1.01500 1.02000 1.02500 1.03000 1.03500 1.04000 1.04500 1.05000 1.05500 1.06000 1.07000 .08000 1.09000 1.10000 1.11000 1.12000 .20000 2 1.02010 1.03022 1.04040 1.05063 1.06090 1.07123 1.08160 1.09203 1.10250 1.11303 1.12360 1.14490 .16640 1.18810 1.21000 1.23210 1.25440 144000 3 1.03030 1.04568 1.06121 1.07689 1.09273 1.10872 1.12486 1.14117 1.15763 1.17424 1.19102 1.22504 .25971 29503 1.33100 1.36763 1.40493 .72800 4 1.04060 1.06136 1.08243 1.10381 1.12551 1.14752 1.16986 1.19252 1.21551...
TABLE 1 Future Value of $1 FV= $1 (1 + ir n/i 5.5% 1 1.01000 1.01500 1.02000 1.02500 1.03000 1.03500 1.04000 1.04500 1.05000 1.05500 1.06000 1.07000 .08000 1.09000 1.10000 1.11000 1.12000 .20000 2 1.02010 1.03022 1.04040 1.05063 1.06090 1.07123 1.08160 1.09203 1.10250 1.11303 1.12360 1.14490 .16640 1.18810 1.21000 1.23210 1.25440 144000 3 1.03030 1.04568 1.06121 1.07689 1.09273 1.10872 1.12486 1.14117 1.15763 1.17424 1.19102 1.22504 .25971 29503 1.33100 1.36763 1.40493 .72800 4 1.04060 1.06136 1.08243 1.10381 1.12551 1.14752 1.16986 1.19252 1.21551...
TABLE 1 Future Value of $1 FV = $1 (1 + i)" n/i 1.0% 1.5% 2.0% 2.5% 3.0% 3.5% 4.0% 4.5% 5.0% 5.5% 6.0% 7.0% 8.0% 9.0% 10.0% 11.0% 12.0% 20.0% 1 2 3 4 5 1.01000 1.01500 1.02000 1.02500 1.03000 1.03500 1.04000 1.04500 1.05000 1.05500 1.02010 1.03022 1.04040 1.05063 1.06090 1.07123 1.08160 1.09203 1.10250 1.11303 1.03030 1.04568 1.06121 1.07689 1.09273 1.10872 1.12486 1.14117 1.15763 1.17424 1.04060 1.06136 1.08243 1.10381 1.12551 1.14752 1.16986 1.19252 1.21551 1.23882 1.05101 1.07728 1.10408 1.13141...
A variety of spectra for an organic compound with molecular
formula C10H16O are presented below. The
experimental accurate mass using (+) APCI source is 153.1280 u. The
1H, 13C, COSY, HSQC and HMBC NMR spectra are given in the following
slides. Propose a structure for this unknown and answer or address
the following questions or requirements:
d. If there are still any questionable assignments, propose
additional NMR experiments which would solve those questions and
briefly explain specifically what correlations you...
1. Suppose that you have information on interest rates {X) and in savings (Y) a sample of 50 households xin % 1.0 2.0 3.0 4.0 5.0 0.010.015.0 5.0 0.0 20.0 0.0 10.0 15.0 16.0 2.0 4.0 3.0 1.0 2.0 6.0 5.0 7.0 2.0 6.0 Y in 4.0 thousands $0.5 5.0 5.0 4.0 6.0 8.0 2.02.52.0 0.8 0.2 1.0 2.0 0.5 1.0 2.0 2.0 2.0 2.0 6.0 16.0 1.0 0.0 Review of the Linear Regression Model Compute the following a. Conditional...
Boxes Task: Evaluate whether you can load various sizes of jars into boxes. For each test, you will input the length, width, and height of a box as well as the diameter and height of a cylindrical jar. The algorithm will determine whether each jar will fit in its corresponding box. The jar can sit upright in the box, or it can lie on its side with its top parallel to one of the sides of the box. Assume that...
Fill out the tables below of the starting material and pure
product by using the given NMR spectrums. Identify if the pure
isomer of methyl nitrobenzoate as ortho, meta, or para.
Complete the table below using your proton NMR spectrum of your starting material. Be sure to include all peaks. Note: The table is expandable. Use the structure below for the letter assignments in your table. Splitting Integration Assignment Peak (ppm) Other Notes -7.95 -7.92 0627 -787 785 7.30 751...