Homework Answers
Part 1
|
Bond fair value |
$300061 |
|
Payments |
Amount |
Present value factor |
= |
Present value |
|
|
Interest |
14400 |
X |
12.46221 |
= |
179456 |
|
Principal |
320000 |
X |
0.37689 |
= |
120605 |
|
Bond price |
$300061 |
320000*9%/2 = 14400
PV of $1 @ i= 5%, n = 20 is 12.46221
PV ordinary annuity of $1 @ i= 5%, n = 20 is 0.37689
Part 2
|
Date |
General journal |
Debit |
Credit |
|
January 01, 2021 |
Investment in bonds |
320000 |
|
|
Discount on bond investment |
19939 |
||
|
Cash |
300061 |
||
|
June 30, 2021 |
Cash |
14400 |
|
|
Discount on bond investment |
603 |
||
|
Interest revenue ((320000-19939)*10%/2) |
15003 |
||
|
June 30, 2021 |
No journal entry required |
||
|
December 31, 2021 |
Cash |
14400 |
|
|
Discount on bond investment |
573 |
||
|
Interest revenue ((320000-19939-603)*10%/2) |
14973 |
Part 3
|
Date |
General journal |
Debit |
Credit |
|
January 01, 2021 |
Investment in bonds |
320000 |
|
|
Discount on bond investment |
19939 |
||
|
Cash |
300061 |
||
|
June 30, 2021 |
Cash |
14400 |
|
|
Discount on bond investment |
603 |
||
|
Interest revenue ((320000-19939)*10%/2) |
15003 |
||
|
June 30, 2021 |
Net unrealized holding gains and losses—I/S |
18905 |
|
|
Fair value adjustment (300061+603-281759) |
18905 |
||
|
December 31, 2021 |
Cash |
14400 |
|
|
Discount on bond investment |
573 |
||
|
Interest revenue ((320000-19939-603)*10%/2) |
14973 |
||
|
December 31, 2021 |
Net unrealized holding gains and losses—I/S |
17389 |
|
|
Fair value adjustment (300061+603+573-264943-18905) |
17389 |
June 30
|
Payments |
Amount |
Present value factor |
= |
Present value |
|
|
Interest |
14400 |
X |
11.95038 |
= |
172085 |
|
Principal |
320000 |
X |
0.34273 |
= |
109674 |
|
Bond price |
$281759 |
320000*9%/2 = 14400
PV of $1 @ i= 5.5%, n = 20 is 11.95038
PV ordinary annuity of $1 @ i= 5.5%, n = 20 is 0.34273
December 31
|
Payments |
Amount |
Present value factor |
= |
Present value |
|
|
Interest |
14400 |
X |
11.46992 |
= |
165167 |
|
Principal |
320000 |
X |
0.31180 |
= |
99776 |
|
Bond price |
$264943 |
320000*9%/2 = 14400
PV of $1 @ i= 6%, n = 20 is 11.46992
PV ordinary annuity of $1 @ i= 6%, n = 20 is 0.31180
Add Answer to:
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
A variety of spectra for an organic compound with molecular formula C10H16O are presented below. The experimental accurate mass using (+) APCI source is 153.1280 u. The 1H, 13C, COSY, HSQC and HMBC NM...
A variety of spectra for an organic compound with molecular
formula C10H16O are presented below. The
experimental accurate mass using (+) APCI source is 153.1280 u. The
1H, 13C, COSY, HSQC and HMBC NMR spectra are given in the following
slides. Propose a structure for this unknown and answer or address
the following questions or requirements:
d. If there are still any questionable assignments, propose
additional NMR experiments which would solve those questions and
briefly explain specifically what correlations you...
A variety of spectra for an organic compound with molecular formula C10H16O are presented below. The experimental accurate mass using (+) APCI source is 153.1280 u. The 1H, 13C, COSY, HSQC and HMBC NM...
A variety of spectra for an organic compound with molecular
formula C10H16O are presented below. The
experimental accurate mass using (+) APCI source is 153.1280 u. The
1H, 13C, COSY, HSQC and HMBC NMR spectra are given in the following
slides. Propose a structure for this unknown and answer or address
the following questions or requirements:
a. Using the most abundant isotopes of C, H and O, what are the
errors in ppm and milli-Daltons for the experimental accurate
mass?...
analyze this NMR & IR S23 CDC13 QE-300 240 UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz....
analyze this NMR & IR
S23 CDC13 QE-300 240 UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
Fill out the tables below of the starting material and pure product by using the given...
Fill out the tables below of the starting material and pure
product by using the given NMR spectrums. Identify if the pure
isomer of methyl nitrobenzoate as ortho, meta, or para.
Complete the table below using your proton NMR spectrum of your starting material. Be sure to include all peaks. Note: The table is expandable. Use the structure below for the letter assignments in your table. Splitting Integration Assignment Peak (ppm) Other Notes -7.95 -7.92 0627 -787 785 7.30 751...
7. What kind of carbons correspond to these chemical shifts? 8. Based on this analysis, the unknown might contain the f...
7. What kind of carbons correspond to these chemical
shifts?
8. Based on this analysis, the unknown might contain the
following substructure:
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
5. Based on this analysis, the compound might be or contain the following substructure: 6. How...
5. Based on this analysis, the compound might be or contain
the following substructure:
6. How many different types of carbons appear to be present?
What are the chemical shifts for these carbons?
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
1. How many different types of protons appear to be present? What are the chemical shifts...
1.
How many different types
of protons appear to be present? What are the chemical shifts for
these protons? What does this indicate (if anything) about the
electronic environment of the protons?
2.
What are the multiplicities for each peak?
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
TABLE 1 Future Value of $1 FV = $1(1+i)" 20.0% 1.20000 1.44000 ndi 1.0% 1 1.01000 2 1.02010 3 1.03030 4 1.04060 5 1.05101 1.5% 2.0% 2.5% 1.01500 1.02000 1.02500 1.03022 1.04040 1.05063 1.04568 1.06121 1.07689 1.06136 1.08243 1.10381 1.07728 1.10408 1.13141 3.0% 1.03000 1.06090 1.09273 1.12551 1.15927 3.5% 4.0% 4.5% 5.0% 5.5% 1.03500 1.04000 1.04500 1.05000 1.05500 1.07123 1.08160 1.09203 1.10250 1.11303 1.10872 1.12486 1.14117 1.15763 1.17424 1.14752 1.16986 1.19252 1.21551 1.23882 1.18769 1.21665 1.24618 1.27628 1.30696 6.0% 7.0%...
A variety of spectra for an organic compound with molecular
formula C10H16O are presented below. The
experimental accurate mass using (+) APCI source is 153.1280 u. The
1H, 13C, COSY, HSQC and HMBC NMR spectra are given in the following
slides. Propose a structure for this unknown and answer or address
the following questions or requirements:
d. If there are still any questionable assignments, propose
additional NMR experiments which would solve those questions and
briefly explain specifically what correlations you...
A variety of spectra for an organic compound with molecular
formula C10H16O are presented below. The
experimental accurate mass using (+) APCI source is 153.1280 u. The
1H, 13C, COSY, HSQC and HMBC NMR spectra are given in the following
slides. Propose a structure for this unknown and answer or address
the following questions or requirements:
a. Using the most abundant isotopes of C, H and O, what are the
errors in ppm and milli-Daltons for the experimental accurate
mass?...
analyze this NMR & IR
S23 CDC13 QE-300 240 UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
Fill out the tables below of the starting material and pure
product by using the given NMR spectrums. Identify if the pure
isomer of methyl nitrobenzoate as ortho, meta, or para.
Complete the table below using your proton NMR spectrum of your starting material. Be sure to include all peaks. Note: The table is expandable. Use the structure below for the letter assignments in your table. Splitting Integration Assignment Peak (ppm) Other Notes -7.95 -7.92 0627 -787 785 7.30 751...
7. What kind of carbons correspond to these chemical
shifts?
8. Based on this analysis, the unknown might contain the
following substructure:
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
5. Based on this analysis, the compound might be or contain
the following substructure:
6. How many different types of carbons appear to be present?
What are the chemical shifts for these carbons?
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
1.
How many different types
of protons appear to be present? What are the chemical shifts for
these protons? What does this indicate (if anything) about the
electronic environment of the protons?
2.
What are the multiplicities for each peak?
UN (43 MIL.) 10.02s, 1H), 7.716.J-2 Hz. ) 2.0 11.5 11.0 10.5 10.0 9.5 9.0 8.5 8.0 7.5 7.0 6.5 6.0 4.0 3.5 3.0 2.5 20 15 100.5 0.0 -0.5 -1.0 -1.5 -2. 5.5 5.0 4.5 fl (ppm)
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