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5 You have a solution of KI that is 0.480 M. How would you prepare 5.00 L of a solution that is 1.50x104 M in iodide ion? ? 1
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Answer #1

Take 1.56 ml of 0.480 M KI and dilute it until 5.0 L of solution to get 1.50x 10'6-4 M KI

since KI is ionic

1 M KI produce 1M K+ and 1M I-

so similarly

1.50x 10'6-4 M KI also produce 1.50x 10'6-4 M of I-

Initial rhaite I kl = 0.480M =M Iné del volume of ki = V,=? Final redanily of kz = 1.50x10th sig Final volume 1 kg = 5.002 =

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