Question

Each plate of a parallel-plate capacator is a square with sidelength ,and the plates are separated by a distance . Thecapacitor is connected to a source of voltage.A plastic slab ofthickness and dielectric constant is inserted slowly between the plates over the time period until the slab is squarely between the plates. While theslab is being inserted, a currentruns through thebattery/capacitor circuit.Assuming that the dielectric is inserted at aconstant rate, find the current as the slab is inserted.Express answer in terms of any or allof the given variables ,,,,, and $epsilon_0$ , the permittivity of free space.

Answer 1

Givena parallel plate capacitor of side length r and the plates areseparated by a distance d.thecapacitor is connected to a voltage of v,now a plastic slabof thickness d and dielectric constant k is slowly inserted overthe time period Δtarea A=r²now the formula for capacitance is C=ε₀AK/dtherefore Q=CVcurrent I as the slab is inserted is Q/Δt

Answer 2

Givena parallel plate capacitorof side length r and the plates areseparated by adistance d.thecapacitor is connected to avoltage of v,now a plastic slabslab of thickness d and dielectric constant kis slowly insertedover the time period Δtarea A=r²now the formula for capacitance is C=ε₀AK/dtherefore Q=CVcurrent I as the slab is inserted is Q/Δt