Question

Changing Capacitance Yields a Current Each plate of a parallel-plate capacator is a square with side length r, and the plates are separated by a distance d. The capacitor is connected to a source of voltage V. A plastic slab of thickness d and dielectric constant K is inserted slowly between the plates over the time period At until the slab is squarely between the plates. While the slab is being inserted, a current runs through the battery/capacitor circuit. (Figure 1) . Figure C 1 of 1

Answer 1

Capacitance (c) = tor (Kx + r-x) { standard results} we know that i change (Q) = CY Current (I) = 0 = y de ar I = v or (a (kx tr-x)) or I - Vear (K-1) da 1 - (K-1) v' vex et where dx = velocily, d Since Velocity is Constant II = (K-1) r² to v dx ot * Please put * Please all the character Carafully. LIKE. THANK YOU.