Question

Draw the shear and moment diagrams including deflected shapes.

12. 3L14 Shear Shear Moment Moment Deflected shape Deflected shape

Answer 1

2P By Equilebrium Equalions Styco sign Convention ↑ the lone 34/4 Rp - P +2P CO V ER TRA E-P) EMACO -MA + P44 - 2P x LEO IMA E - IPL SFD St Calculation (shear force) Take a section at distance & from B & at distance x, from A SFX ( Between stor s sign corren Sfx = -2P IPL/A ( from Right 342. SEX ( Between A toc) Sfx, et (-P) = RA BM) Id the 1 from Left? 1 ↑ the I tone BM Calculation sign convention for (BM) Bending Moment - the sagging BMx Bet Bto) Deflected upward LIIIII BMx = 2P2 at xe0 Bmco x= 31 BM = 2P 3 L e 3PL Deflected shape BMx ( Bet A to C) BMX, E -MA & RAX, 2 +7PL - Por, at se, co BMX, E IPL/4 x = YA BMX, c 3PL/

HA TOIMIT Take section at a from point D t x from c. Sign Convention for shear force 4 Bender moment calculation is same as previous question Sf calculation Sf = P (Bet a to c) Sfx, Papco ( Bet c to AJ sf bet B to D is o due to no force SED BMD BM Calculation BM e (bet B to D) EO ( no forces B Moc E bet Doc) = -Pa at xco BMC o at xa 42 BM BMx, (bet 6 to A) = -P ( ½ + 2) + PR at x,co BM = -PL/ downaward at x, = 44 BM G - PL - deflection By Equilebrium equation {fy co RATRB=0-0 RAL +2m=0 SED Sf Calculation Sfx = &RA & 2M (A to B). KUI III | B||||||| Bm cala BM BM Calaration BMX & RAX at xeo Bм со upwone at xeL BME 2M Defleched Shape

R-B By equslebrium equations RATRB EO - Mgco RAX L t mco IRA C - M/L (RB = M L SF calculation SAC RA ( Bet Ato C) JSF 2 - M SF xe &RA ( Bet chog) (Sfx, < – M/ SED BM Calculation -M/2 BMD BM. & A to C) xco BMEO BMx = RAR x= 1 BM=-M BMx, & C to B) BMx, = RA ( 1 + x) IM BMx, 2 M ( + + 4) + M. BM, at x, co is my BM, at x, = 4 is o Deflected shape