Question

Has to be in Unix!

Lab 7 Programs 1. Create a prints.c file, and copy the following into it: #include <stdio.h> int main(int argc, char * argv[]) { double x = 1.0, y = 5.1e7; float pi = 3.14159f; int i=0, j=5115; short int m= 6; unsigned long int n = 51151151; return 0; Now, write printf commands to: • print x with a field width of 6; print y with a field width of 8 and a precision of 4; print pi with a precision of 2; • print i with a field-width of 6; • print j with a precision of 6; • print m; print n. 2. Write a program that asks the user to enter two dates in YYYY-MM-DD format), and then prints which date is earlier. Your program should print an error message if the user enters an invalid date (like 2019-15-99). 3. Write a program that asks for a (floating-point) starting point, and then prints the result of the following computation 100 times: v=(5.0-v)x(ho 4. Write a program that asks the user to enter a numeric grade, and then prints the corresponding letter grade.

Answer 1

Solution 1):-

C Code :-

#include <stdio.h>

int main(void) {
   double x = 1.0, y = 5.1e7;
   float pi = 3.14159f;
   int i = 0, j = 5115;
   short int m = 6;
   unsigned long int n = 51151151;
   printf ("x = %6lf\n", x);
   printf("y = %8.4lf\n", y);
   printf("pi = %.2f\n", pi);
   printf("i = %6d\n", i);
   printf("j = %.6d\n", j);
   printf("m = %d\n", m);
   printf("n = %lu\n", n);
   return 0;
}

/************ Output of the program *************
* x = 1.000000
y = 51000000.0000
pi = 3.14
i = 0
j = 005115
m = 6
n = 51151151
******************************************************/

Solution 2):-

C Code:-

#include<stdio.h>

struct date
{
int day;
int month;
int year;
};

int main()
{
struct date d1,d2;

printf("Enter first date(YYYY-MM-DD):");
scanf("%d-%d-%d",&d1.year,&d1.month,&d1.day);
printf("nEnter second date(YYYY-MM-DD):");
scanf("%d-%d-%d",&d2.year,&d2.month,&d2.day);

if ((d1.year > d2.year) || ((d1.year==d2.year) && (d1.month > d2.month)) || ((d1.year==d2.year) && (d1.month == d2.month) && (d1.day>d2.day)))
{
printf("%04d-%02d-%02d", d2.year, d2.month, d2.day);
}
else
{
   printf("%04d-%02d-%02d", d1.year, d1.month, d1.day);
}

return 0;
  
}

/***************************** Output of Program ***********************

Enter first date(YYYY-MM-DD): 1998-04-10
Enter second date(YYYY-MM-DD):1998-04-04
1996-04-04

Enter first date(YYYY-MM-DD): 1996-06-10
Enter second date(YYYY-MM-DD): 1996-04-01
1996-04-01

Enter first date(YYYY-MM-DD): 1996-04-01

Enter second date(YYYY-MM-DD): 1996-04-01

1996-04-01

***************************************************************************/

I have solve the first two question with all the subparts, please post next two question AS SEPERATE QUESTION