PYTHON 3 CODING
Review the following tree and then implement Depth First Traversals. Your program should display the output from Inorder to Preorder and Postorder.
Include the following items in your answer:
Use the following steps to help with your solution:
# class for Node
class Node:
def __init__(self, data):
self.data = data
self.left = None
self.right = None
# adding Node to tree
def addNode(root, node):
if root is None:
root = node
else:
if root.data < node.data:
if root.right is None:
root.right = node
else:
addNode(root.right, node)
else:
if root.left is None:
root.left = node
else:
addNode(root.left, node)
# inOrder tree traversal
def printInOrder(root):
if root:
# First recur on left child
printInOrder(root.left)
# then print the data of node
print(root.data, end=" ")
# now recur on right child
printInOrder(root.right)
# postOrder tree traversal
def printPostOrder(root):
if root:
# First recur on left child
printPostOrder(root.left)
# the recur on right child
printPostOrder(root.right)
# now print the data of node
print(root.data, end=" ")
# preOrder tree traversal
def printPreOrder(root):
if root:
# First print the data of node
print(root.data, end=" ")
# Then recur on left child
printPreOrder(root.left)
# Finally recur on right child
printPreOrder(root.right)
if __name__ == "__main__":
n = int(input("Enter the number of nodes you want to Enter :
"))
data = input("Enter the data for Node 1 : ")
root = Node(data)
for i in range(2, n+1):
data = input("Enter the data for Node {} : ".format(i))
node = Node(data)
addNode(root, node)
print("\nPreOrder traversal of binary tree is")
printPreOrder(root)
print("\n\nInOrder traversal of binary tree is")
printInOrder(root)
print("\n\nPostOrder traversal of binary tree is")
printPostOrder(root)


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