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Which of the following is the correct equilibrium constant for the following reaction run at pH = 7.00 and 25.0 degrees C? Th

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Answer #1

We know that,

Delta G° = - R * T * ln Kc

Where Delta G° is standard Gibbs free energy. R is gas constant with value 8.314 J/mol K . T is temperature in Kelvin and Kc is equilibrium constant.

Delta G° = - 24.7 KJ = -24700 J

T = 25° C = 298 K

Now,

-24700 = - 8.314 * 298 * ln Kc

ln Kc = 9.96944

Kc = e^(9.96944) = 2.14*10^4 ... Answer

Hence, option (a) is correct.

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