Question

A parallel plate capacitor has-Q on the left plate and +Q on the right. Treat the problem as infinite plates with the same surface charge density Graph potential and field as a function of distance from the left plate along the x- axis. Make sure you plot both between and outside the plates. For the electric field, use a positive value to indicate that the field points to the right. For the potential, take the left plate as zero potential. For full credit, you need both for the correct sign and the correct x-dependence. +Q Plot values of E-field and potential along this line in graphs below a) [5 points] E-field plot (E>0 means field points to right) E b) [5 points Potential plot (left plate has V 0)

Answer 1

@ Electric field between plates of capacitas (piruliers is from pasilies AEO Outsids plates E=0 to to regaliu AS ® According to relation betweers feeld and patential & Patential increases V=-Eox opposite to field