Question 7 What is the value (in V) of Eºcell for the following reaction? Zn2+ (aq)...

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Question 7 What is the value (in V) of Eºcell for the following reaction? Zn2+ (aq) + Pb (s) → Zn (s) + Pb2+ (aq)

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Answer 1

Answer #1

For the given cell reaction

Cathode reaction: Zn²⁺ (aq) + 2e $\to$ Zn (s) ; E^o_Zn2+/_Zn = - 0.76 V.

Anode reaction: Pb (s) - 2e $\to$ Pb²⁺ (aq) ; E^o_Pb²⁺/_Pb = - 0.13 V

E^o_cell = E^o_cathode - E^o_anode = - 0.76 - (-0.13) = - 0.63 V.

Answer 2

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