Question

Question: The composite bar ABC is made of same material having E- 100 GPa. When the load was applied, the diameter for segment AB decreased by 0.025mm, calculate the final diameter of segment BC 20 mm 15 mm 100 kN 100 kN B 200 mm C A 350 mm

Answer 1

For segment AB 1001 (+) & Fx = 0; P – 100 = 0 P = 100 KN P Linear strain, Linear strain, & - E - (100 x 103) TT(20)4 < (100 x 103) nie = 0.003183 mm/mm Α Ε -0.025 Lateral strain, Ed = -0.001250 mm/mm 20 Poisson's ratio Poisson's ratio -0.001250 - 0.3927 V = -0.001250 0.003183 0.3927 €1

For segment BC (++) {Fx = 0; P - 100 = 0 P = 100 KN AS TODAY P - Linear strain, E = = (100 x 103) - Tt(15) x (100 x 103) = 0.005659 mm/mm AE Lateral strain, Ed = -VĘ = -0.3927(0.005659) = -0.002222 mm/mm But But Ed Ed - daa - 0.002222 - 0'7535 d' - 15 -0.002222 = d = 14.96667 mm d' = 14.96667 mm 15