Please note :-
Two resistors in series Equivalent Resistance(Req) = R1 + R2 .................... (1)
Two resistors in parallel Equivalent Resistance(Req) = 1/R1 + 1/R2 = R1R2/(R1+R2) ..............(2)
Given :-
R1 = 1 Ω
R2 = 3 Ω
R3 = 7 Ω
Different combinations possible as below :-
1.) Put R1,R2 & R3 in series.
2.) Put R1,R2 & R3 in parallel.
3.) [R1,R2 in series] parallel with R3
4.) [R2,R3 in series] parallel with R1
5.) [R3,R1 in series] parallel with R2
6.) [R1,R2 in parallel] series with R3
7.) [R2,R3 in parallel] series with R1
8.) [R3,R1 in parallel] series with R2
Therefore you can make 8 resistors.
Part b.)
Now lets calculate the Equivalent Resistance of each combination using the formulae (1) & (2) for Req in series and parallel.
1.) Equivalent Resistance = R1 + R2 + R3 = 11 Ω
2.) Equivalent Resistance = 1/R1 + 1/R2 + 1/R3 = 21/31 Ω
3.) Equivalent Resistance = 28/11 Ω = 2.54 Ω
4.) Equivalent Resistance = 10/11 Ω = 0.9 Ω
5.) Equivalent Resistance = 24/11 Ω = 2.18 Ω
6.) Equivalent Resistance = 31/4 Ω = 7.75 Ω
7.) Equivalent Resistance = 31/10 Ω = 3.1 Ω
8.) Equivalent Resistance = 31/8 Ω = 3.875 Ω
4. Assume you have 3 resistors with the resistances 1 Ω, 3 Ω and 7 Ω,...
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Rc circuit
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