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2. A block of mass 15.0 kg is being pulled up a flat incline of angle 30.0? and coefficient of kinetic friction 0.120 by a string. The tension in the string is 120 N, and is directed parallel to the incline, as shown in the diagram below. (a) What is the value of the force exerted on the block by the incline? (That is, what is the block�s apparent weight?) (b) What is the magnitude of the block�s acceleration?

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Answer #1

Normal force = 15gcos30 = 127.31 N perpendicular to incline

friction force = 0.120 x 127.31 = 15.28 N along incline

so , net force = sqrt(127.31^2 + 15.28^2) = 128.22 N

b)

120 - 15.28

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