Question

The puns shot in there beio dlvers a head of 350 ft to the water Deternine the pones that the oumo adds to the water. The difterence in elevation of the two ponds is 300 ft. -10 Pump 1.5 Po length 400 0.8Pipe roughinass-0 ho

Answer 1

h_p = 350 ft z_2 - z_1 = 300 ft l = 400 ft D = 1 ft e = 0 P_1/v + v_1^2/2g + z_1 + h_p = p_2/v + v_2^2/2g + z_2 + h_1 - (1) h_2 = fl v^2/2g D + Sigma k_L v^2/2g - (2) P_1 = P_2 = 0 v_1 = v_2 = 0 z_2 - z_1 = 300 ft h_p = 350 ft h_p = (z_2 - z_1) + h_L 350 = 300 + h_L = > h_L = 50 ft Sigma k_L = 5 + 0.8 + 1 + (4 times 1.5) = 12.8 h_L = 6.2111 fv^2 + 0.1987 v^2 350 = 300 + 6.211 fv^2 + 0.1987 v^2 v^2 (6.2111 f + 0.1987) = 50 - (4) Re = V_D/v = V times 1/1.2 times 10^-5 = 82644.6281 v Assuming f = 0.015 V^2 times (6.2111 times 0.015 + 0.1987) = 50 V = 13.0885 ft/s Re = 82644.6281 times 13.0885 = 1081701.685 e/D = 0 f = 0.0114898 ~ 0.015 \r\n Assuming f = 0.012 V^2(6.2111 times 0.012 + 0.1987) = 50 v = 13.527 ft/s Re = 82644.6281 times 13.527 = 1117933.884 f = 0.01142 Assuming f = 0.011 V^2 (6.211 times 0.011 + 0.1987) = 50 v = 13.6839 ft/sec Re = 82644.6281 times