Question

STA I Tet 4F 19 Nane Section ) Constrct a 90% condidence iterval for . The known population standard deviation e is 10. The sample data is 60and s-90 A) 602.64 B) 60 2.07 601.54 D) 601.73 E) 60 2.26 2) Constrct a 70% confidence interval for p. The known population standard deviation o 12. The samgple data is -60and n-130 A) 602.43 E) 60 2.01 B) 60+0.85 C601,09 D) 601.27 3) A confidence interval foru has the form +Ewhere E is the erree term. Find he minimum sample size n that must be taken so that ES2 for a 90% confidence interval where the population standard deviation o-18. A) 220 C) 165 B) 232 D) 258 E) 502 4) A normally distributed population has an unknown standard deviation The sample data is tX15, s-6 and -4) Find the 1-value to coestruct a 95% confidence interval for the population mean A)3.654 B) 2.571 )2543 D) 1960 E) 3.182 5) A normally distributed population has an unknown standard deviation. The sample data is tx-20, s-9 and n-30) Constract an 80 % confidence interval for the population mean A) 20 2.98 B) 20 2.75 C)20 1.54 D) 20 2.15 E) 20 2.36 6) A normally distributed popalation has an unknown standard deviation. The sample data is (x -30,s-10 andn=140) Construct a 90% confidence interval for the population mean A) 30 1.78 B)) 30 2.94 C)) 30 1.40 D)) 30 2.19 E)) 30 2.05

Answer 1

J140 95-5. confidence in caval 0=10; n=90; 2=60 2:1.96 for osv. confidence CI=5+2412. In 5)60+ 1.96 x 10 =579337 => 60+ 2.066 =) 60+ 2.07 6) 9001 confidence integral *=30, 5=10 ;n= 140 CI-517 9=1.64 for 90% confidence - 30+1.64 x 10 -) 30+ 1.386 ~ 30+ 1.40 3) Manimum esrol E= 242.50 IE22 2=1164x18 n=217,87 e 220 4 1=15, S=6; and n=4 ta 15-18.5 15-9.1 . 5/5n = 6th a blitt a lotbe 3) (I for 951. = 1096 154196x =) 15+ 5.88 5) 804. confidence interval X=20,s=9, n=30 I For sol. c.I CI - + 2db | 2d12=1.29 = 20$ 1.29x 5 =18 2 = 20 2.11 ~ 20+ 2.15

2) Toy confidence interval ZE 1.04 X=60; n =B0 ;S=12 C.I = I 2012. = 60+ 1.64 x = 60 I 1.09
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