Female drosophila has two X chromosome and the male has one X -chromosome.


Obj. 37. In Drosophila forked (F) bristles is X-linked and dominant. If a virgin female homozygous...
We crossed pure-bred female flies with yellow body and
forked-shaped bristles with male flies extra bristles. The
subsequent F1 flies showed all normal phenotypes except that all of
the F1 males are yellow-body. We crossed again the normal F1
females with males homozygous for yellow body, extra bristles, and
forked bristles as a testcross. The number of each category of F2
progeny is shown below. The mutant allele for yellow body is y; the
mutant allele for extra bristles is...
In Drosophila melanogaster, the recessive X-linked alleles white (w), miniature (m) and forked (f) give the phenotypes white eyes, miniature wings and forked brushes. The recombination between the w and m loci is 35%, and between the m and f loci, 20%. Wild-type males were crossed with females from a strain that was homozygous recessive for the three alleles, then the F1 flies were sibling mated. What phenotype frequencies are expected in F2 a) if there is no interference, and...
2.In Drosophila, yellow body is due to an X-linked gene that is recessive to the gene for gray body. (a) A homozygous gray female is crossed with a yellow male. The F1 are intercrossed to produce F2. Give the genotypes and phenotypes, along with the expected proportions, of the F1 and F 2 progeny. (b) A yellow female is crossed with a gray male. The F1 are inter- crossed to produce the F2. Give the genotypes and phenotypes, along with...
A virgin Drosophila female whose thorax bristles are very short is mated with a males having normal (long) bristles. The F1 progeny are 1/3 short-bristle females, 1/3 long bristle females, and 1/3 long bristle males. A cross of the F1 long bristle females with their brothers gives only long bristle F2 progeny. A cross of short bristle females with their brothers gave 1/3 long bristle females, 1/3 short bristle females, and 1/3 long bristle males. Explain what is going on...
Cinnabar eyes (cn) and reduced bristles (rd) are autosomal recessive characters in Drosophila. A homozygous wild-type female was crossed to a reduced, cinnabar male, and the F1 males were then crossed to the F1 females to obtain the F2. Of the 400 F2 offspring obtained, 292 were wild type, 9 were cinnabar, 7 were reduced, and 92 were reduced and cinnabar.
Finally, bow-legs is hypothesized to be X-linked recessive in Drosophila melanogaster. The P1 virgin females were, once again, homozygous wild type but the males were bow-legged. There were 52 wild type males and 67 wild type females in the F1 generation. The F2 generation contained 30 wild type males, 75 wild type females, 40 bow-legged males and no bow-legged females. Does this data support or reject the hypothesis? Use chi square to prove your position.
A female Drosophila melanogaster is crossed with a male. The male's phenotype and genotype are unknown, while female's phenotype is known to be red eyes, straight wings, shaved bristles, and an ebony body. So, then the female's genotype should be Xw+Xw ; c+ c; ee; sdsd. Given that red eyes are dominant to white eyes, straight wings are dominant to curved wings, long bristles are dominant to shaven bristles, and a gray body is dominant to an ebony, draw a...
Question 5 In Drosophila, ebony body (e) and rough eyes (r) are encoded by linked autosomal recessive genes on the third chromosome and are completely linked at O map units apart. A homozygous ebony female was crossed to a homozygous rough male. The F1 were all wild ty The F1 females were crossed to ebony, rough males. Give the phenotypes and their proportions in the F2. ebony, rough 20%, wildtype 20%, ebony 30%, rough 30% ebony, rough 30%, wildtype 30%,...
A mutation in the Drosophila bristle gene (fb) (which is X-chromosome linked) causes a recessive forked bristle phenotype (rather than the normal type of bristle). Another mutation in Drosophila autosomal body color gene (BR) causes a recessive brown color body (rather than the normal black body). A geneticist carried out the following cross: X+ / Y ; BR/br x X+/ Xfb ; BR/br If total of 240 F1 progeny were obtained, the “expected” numbers are: normal bristle male progeny -...
Please answer #1-6 and explain and indicate which # you
are answering. Thank you so much!! I updated the size of the
text.
In Drosophila, a male with yellow body is crossed with a female with extra and forked bristles. In the Fl generation both male and female offspring are all completely normal. A F1 female is then crossed with a male with yellow, extra bristle, and forked bristle that is homozygous for all alleles. 1000 progeny are produced in...