Calculate Qip (ion product) for a mixture containing 25 mL of 5.0 × 10–9 M AgNO3 and 75 mL of 6.5 ×10–8 M KI. Decide whether AgI will precipitate from this mixture. The Ksp for AgI is 8.3 × 10–17
show all work




Calculate Qip (ion product) for a mixture containing 25 mL of 5.0 × 10–9 M AgNO3...
Consider the titration of 25.00 mL of 0.0925 M KI with 0.0695 M AgNO3. Calculate pAg+ at the following volumes of added AgNO3: (a) 30.00 mL; (b) Ve; (c) 35.27 mL. Ksp (AgI) = 8.3×10-17
Consider the titration of 25.00 mL of 0.07920 M KI with 0.05410 M AgNO3. Calculate pAg+ at a) 25.00 mL > ?? b) Ve > M1V1 = M2V2 (0.07920)(0.025)=(0.05410)(Ve) --------> Ve = 36.60 mL c) 45.00 mL > ?? of AgNO3 added (Ksp= 8.3*10-17). Show ALL work. pAg+ = -log[Ag]
Consider the titration of 25.00 mL of 0.082 M KI with 0.051 M AgNO3. Ksp for AgI is 8.3 X 10−17 Write the chemical reaction occurring in the beaker during the titration. Calculate the equivalence point volume. (about 40 mL, calculate to 4 significant figures) Calculate the pAg a) Before AgNO3 is added (Boom, Why?) b) At the volume half way to the equivalence point (14.4) c) At the equivalence point (8.04) d) 5 mL after...
The Ksp of AgI is 8.3× 10–17. You titrate 25.00 mL of 0.08160 M NaI with 0.05190 M AgNO3. Calculate pAg after the following volumes of AgNO3 are added: (a) at 35.10 mL (b) at Ve (volume at equilibrium) (c) at 47.10 mL
A 25.00 mL solution of 0.08680 M NaI is titrated with 0.05120 M AgNO3 . Calculate pAg+ following the addition of the given volumes of AgNO3 . The ?sp of AgI is 8.3×10^−17 36.00 mLpAg+ = ? ?e pAg+ = ? 47.40 mL pAg+ = ?
Calculate the equilibrium concentrations of each ion in the final solution resulting from the mixing of 40.00 mL of 0.0450 M MgI2 and 60.00 mL of: (3) Ksp a) 0.0400 M KOH Mg(OH)2 1.8 x 10-11 b) 0.0500 M AgNO3 AgI 8.3 x 10-17 c) 0.0600 M Pb(NO3)2 PbI2 7.9 x 10-9
The Ksp of AgI is 8.3× 10–17. You titrate 25.00 mL of 0.08870 M NaI with 0.05050 M AgNO3. Calculate pAg after the following volumes of AgNO3 are added: (a) 37.20 ml (b) Veq (c) 47.20 ml
A 25.00 mL solution of 0.08050 M NaI is titrated with 0.05000 M AgNO3 . Calculate pAg+ following the addition of the given volumes of AgNO3 . The ?sp of AgI is 8.3×10−17 . 35.80 mLpAg+= ?epAg+= 47.90 mLpAg+=
Calculate the equilibrium concentrations of each ion in the final solution resulting from the mixing of 40.00 mL of 0.0450 M MgI2 and 60.00 mL of: b) 0.0500 M AgNO3 AgI 8.3 x 10-17 c) 0.0600 M Pb(NO3)2 PbI2 7.9 x 10-9
I need help please To a solution containing 0.15 M Ci- ion and 0.15 M Br- ion, you add some solid AgNO3. Ksp for AgCl is 1.6 * 10^-10 and for AgBr is 5.0*10^-13. the addition of solid doesn't change the total volume. a) which component AgCl or AgBr precipitates first? b) what is the concentration of the first anion to precipitate when the silver halide of the second anion starts to precipitate?