Question

Playing With Arrays

The following problems are to give you practice with programming with arrays. Write a program to:

1.Ask the user for numbers and place them in an array sequencially.

2.Next, print out the values in the array in the order they are stored.

3.Search the array for the postion containing the smallest value.

4.Print out the position where the smallest value was found.

5.Swap the smallest value with the value in the first postition of the array.

6.Print out the array in the order they are now stored.

7.Reverse the elements of the array.

8.Print out the array in the order they are now stored.

9.Add 1 to every odd number in the array.

10.Print out the array in the order they are now stored.

11.Repeatedly ask the user for a number and printout the position in the array where that number is stored. Print "Not Found" if the number is not in the array.
Quit when the user enters a sentinel value (such as -1).

Directions

You must write a method to print out the elements of the array in the order they are stored. Use that method every time the array is printed.

Test your program thoroughly. Include a screen-grab printout of your tests and the results.

Hints:

Build up the program incrementally. Just do step 1 above and test it. Once working, add in step 2. Then test it. Then step 3, and so on.

Thanks for the help

Answer 1

NOTE: I have completed code according to your requirement and assuming the language is Java. If not, please let me know the language required i will code accordingly. Please check and let me know if you have any questions. I will acknowledge back within 24 hours. Thanks for your patience.

Code:
import java.util.Scanner;

class Main{
public static void main(String[] args){
// declaring variables
Scanner sc = new Scanner(System.in);
int n, min_pos = 0, min;
int[] arr = new int[100];
int[] temp_arr = new int[100];
  
// checking how many numbers user want to enter
System.out.println("Enter how many values? ");
n = sc.nextInt();
// getting the set of numbers user want to enter
for(int i = 0; i < n; i++){
System.out.println("Enter "+(i+1)+ " number: ");
arr[i] = sc.nextInt();
}
System.out.println("Given array elements are:");
//printing the numbers stored in array
for(int i = 0; i < n; i++)
System.out.println(arr[i]+ " ");
// searching array for smallest number position
min = arr[0];
for(int i = 1; i < n; i++)
if(arr[i] < min){
min_pos = i;
min = arr[i];
}
// printing the smallest number position
System.out.println("Smallest number is at position: "+ min_pos);
// swap smallest value with value in first position of the array
int t = arr[0];
arr[0] = arr[min_pos];
arr[min_pos] = t;
// printing the numbers in arrays again
System.out.println("Array elements after swapping with min value position is:");
for(int i = 0; i < n; i++)
System.out.println(arr[i]+ " ");
// reversing numbers in array
int k = 0;
for(int j = n-1; j >= 0; j--)
temp_arr[k++] = arr[j];
for(int i = 0; i < n; i++)
arr[i] = temp_arr[i];
// printing the array in the order now it is stored
System.out.println("Array elements after reversing:");
for(int i = 0; i < n; i++)
System.out.println(arr[i]+ " ");
// add 1 to every odd number in the array
for(int i = 0; i < n; i++)
if(arr[i] % 2 == 1)
arr[i] += 1;
// printing the array in the order it is stored now
System.out.println("Array elements after adding 1 to odd numbers:");
for(int i = 0; i < n; i++)
System.out.println(arr[i]+ " ");
int x;
while(true){
System.out.println("Enter a number to check in array: ");
x = sc.nextInt();
if(x == -1) break;
int i = 0;
for(; i < n; i++)
if(arr[i] == x){
System.out.println("Given number found and it is position "+ i);
break;
}
if(i == n)
System.out.println("Not Found. Try again");
}
}
}

Code output screenshot: