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Problem 4 (25 points). What will the following code print? Why? Identify the line where the vulnerability is. Explain the vulnerability. Show how the vulnerability can be eliminated Algorithm 2 Example vulnerability l.void called (int foo) 2. if (foo 1) printf(foo) 3. else printf(bar S.int main O 6. called(2): 7. return 0:)

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Answer #1

The code will print foo. This is because of the if statement in the function.

if(foo=1) here the statement is not making comparison but is doing assignment, assigning value 1 to foo. the statement will be aways true and if statement will be executed.

To solve this, make if statement as:

if(foo == 1)

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