Question

(10 pts) An engineer has to solve an emergency, for which he needs a circuit that performs a logical function. Only one integrated circuit with four comparators, which have the output values ​​of 5V and 0V, respectively. Fortunately for you, the input signals to the circuit, VA; VB, and VC, they have precisely high and low voltages of 5 V and 0 V, respectively. Also in he found many resistances in his warehouse, all the same. The circuit you built or shown below. All resistances are from same value, and the reference voltages of 3 V and 2 V were obtained by means of dividers of voltage, not shown to simplify the diagram. > What logical function are you performing? Justify your answer.

VA VB 3 V VC-W- 3 V 3 V- Vo 2 V

Answer 1

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The first comparator on top outputs a 1 if Va is ON. THus, this output = Va. The comparator at the bottom always outputs a 1, since 3V > Vb/2. The 3rd comparator adds the Vc and the output of the second comparator and compares it to 3V. Since output of second comparator is always 1, output of 3rd comparator is always 0. Now, at the -ve input of the last comparator, we have the signals A and 0 added up, to give A. Thus, A is being compared to 2V. This will output a '1' if A is 1, else 0. Thus V0 = VA

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