Question

9. What output is produced by the following code? (2 points) int waitTime 24 try SttrT block entered y if (waitTime> 25) throw new Exception("Time Limit Exceeded."); System.out.println("Leaving try block."); catch(Exception e) System.out.println("Exception:"+ e.getMessage0); System.out.println("After catch block")

Answer 1

HelloWorld.java (/Desktop) -gedit File Edit View Search Tools Documents Help HelloWorld.java x public class Helloworldt public static void main(String [Jargs) int waitTime-24; try //code to try System.out.println("try block İf(waitTime-25) // if stem outprintina oed: this wil entered" this will printed at biggning bikgning throw new Exception("Time Limt Exceeded"); Iif condition satisfied then throw new exception System.out.printin("Leaving try block"): otherwise this statement will printed catch(Exception e) //code to handle errors System.out.printin("Exception: "+e.getMessageO): /if error occurs then this exception will be printed JavaTab Width: 8 Ln 7, Col 75 INS 令回40 12:27 AM, nagesh。

nagesh@nagesh-TravelMate-4740: /Desktop File Edit View Search Terminal Help nagesh@nagesh-TravelMate-4740:-$ cd D* nagesh@nagesh-TravelMate-4740:-/DesktopS javac Helloworld.java javac: file not found: Helloworld.java Usage: javac <options> <source files> use help for a list of possible options nagesh@nagesh-TravelMate-4740: /Desktops javac Helloworld.java nagesh@nagesh-TravelMate-4740:-/Desktop$ java Helloworld try block entered Leaving try block nagesh@nagesh-TravelMate-4740:~/Desktop$ nagesh@nagesh-TravelMate-4740:-/Desktops 令四140 12:27 AM, nagesho

OUTPUT:

try block entered

Leaving try block

Explanation:

we intiated Wait Time to 24.

In try block first we are printing "try block entered"

if IF condition fails then "Time limit Exceeded" will be printed

But the if condition is (Wait Time >25) so it failed and "Leaving try block" is printed.

there is no error occuerd so the catch block will not executed.

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