HomeworkLib
Question

1.2 A coil of 5000 turns is wound in the form of an air-cored torus with a square cross section. The inner diameter of the torus is 60 mm and the outer diameter is 100 mm. The coil current is 0.25 A.

media%2F1c2%2F1c2f9015-8897-44eb-891c-60

engineering   Electrical-Engineering   
0 0
Add a comment Improve this question Transcribed image text
Next > < Previous
Sort answers by oldest

Homework Answers

Answer #1

inner dametw d 60isA 囫 dy = 50mm . Thickness of the toruu, tr) torus ts the toxua hare are cxok 400x166m 4x151m, Na total number of turns S0o0 [Le lengtǐ, at the meandia meam radiu 30+50 M M 40mm . aur-cos ed teras 2RYm x .25 4.25 x 16 3T a) mcjmutic fieldey pr nit volune at tue mear diamelr the torus

0 0
Add a comment
Know the answer?
Add Answer to:
1.2 A coil of 5000 turns is wound in the form of an air-cored torus with...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Log In

Sign Up

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions

  • 1.2 A coil of 5000 turns is wound in the form of an air-cored torus with...

    1.2 A coil of 5000 turns is wound in the form of an air-cored torus with a square cross section. The inner diameter of the torus is 60 mm and the outer diameter is 100 mm. The coil current is 0.25 A.

  • A solenoidal coil with 23 turns of wire is wound tightly around another coil with 320...

    A solenoidal coil with 23 turns of wire is wound tightly around another coil with 320 turns. The inner solenoid is 25.0 cm long and has a diameter of 2.30 cm . At a certain time, the current in the inner solenoid is 0.100 A and is increasing at a rate of 1700 A/s Calculate the emf induced in the outer solenoid by the changing current in the inner solenoid

  • A solenoidal coil with 30 turns of wire is wound tightly around another coil with 300...

    A solenoidal coil with 30 turns of wire is wound tightly around another coil with 300 turns. The inner solenoid is 24.0 cm long and has a diameter of 2.30 cm . At a certain time, the current in the inner solenoid is 0.150 A and is increasing at a rate of 1600 A/s . For this time, calculate the average magnetic flux through each turn of the inner solenoid.For this time, calculate the mutual inductance of the two solenoids;For...

  • A solenoidal coil with 29 turns of wire is wound tightly around another coil with 310...

    A solenoidal coil with 29 turns of wire is wound tightly around another coil with 310 turns. The inner solenoid is 24.0 cm long and has a diameter of 2.00 cm . At a certain time, the current in the inner solenoid is 0.130 A and is increasing at a rate of 1800 A/s . A) For this time, calculate the average magnetic flux through each turn of the inner solenoid. B) For this time, calculate the mutual inductance of...

  • 1)A solenoidal coil with 22 turns of wire is wound tightly around another coil with 350...

    1)A solenoidal coil with 22 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 25.0 cm long and has a diameter of 2.30 cm . At a certain time, the current in the inner solenoid is 0.110 A and is increasing at a rate of 1600 A/s . a)For this time, calculate the average magnetic flux through each turn of the inner solenoid. b)For this time, calculate the mutual inductance of the two...

  • A coil of 40 turns of wire is wound about a circular form. The average diameter...

    A coil of 40 turns of wire is wound about a circular form. The average diameter of the individual loops is 30.5 cm. Calculate the magnetic moment of the coil when it carries a current of 2.50 A.

  • A solenoidal coil with 30 turns of wire is wound tightly around another coil with 350...

    A solenoidal coil with 30 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 23.0 cm long and has a Part A diameter of 2.10 cm. At a certain time, the current in the inner solenoid is 0.120 A and is increasing at a rate of 1800 A/s. For this time, calculate the average magnetic flux through each turn of the inner solenoid. Express your answer in webers. Vη ΑΣφ' Фв - Wb...

  • Part A A solenoidal coil with 25 turns of wire is wound tightly around another coil...

    Part A A solenoidal coil with 25 turns of wire is wound tightly around another coil with 350 turns. The inner solenoid is 22.0 cm long and has a diameter of 2.40 cm. At a certain time, the current in the inner solenoid is 0.110 A and is increasing at a rate of 1700 A/s. For this time, calculate the average magnetic flux through each turn of the inner solenoid. Express your answer in webers. Ivo A20 ? Wb Submit...

  • Thirty-seven turns of insulated wire 0.100 cm in diameter are tightly wound to form a flat...

    Thirty-seven turns of insulated wire 0.100 cm in diameter are tightly wound to form a flat spiral. The spiral fills a disk surrounding a circle of radius 5.00 cm and extending to a radius 8.70 cm at the outer edge. Assume the wire carries a current I at the center of its cross section. Approximate each turn of wire as a circle. Then a loop of current exists at radius 5.05 cm, another at 5.15 cm, and so on. Numerically...

  • Two air-cored coils are disposed relatively to each other so that 60% of the flux in...

    Two air-cored coils are disposed relatively to each other so that 60% of the flux in one coil links all the turns of the other coil. Each coil has a mean diameter of 2cm and a length of 50 cm. If there are 2000 turns of wire on one coil, calculate the number of turns required on the other coil to give a mutual inductance of 20 mH

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT