Question

An object placed 20 cm in front of a lens results in an image being formed 24 cm behind the lens. Each surface of the lens is convex (bulging away from the optical plane) with the same radius of curvature, and the index of refraction of the glass composing the lens is Tiens =1.4. What is the radius of curvature of either side of this lens (to the nearest tenth of a cm)? Note, once again, the focal length of a lens can be found from the lensmaker's equation, which, for a bi-convex lens in air with the same radii of curvature on its front and back sides, is given by } = (niens - 1)).

Answer 1

Gol Off Given VE 24 cun 1 24 20 24420 (24)(20) (241020) (24+20 10.9 cm in givn eg Now puting the (14-1) 2 10.9 872 cm 1

Sol Civon wror ferul Eren V u u-f (4)(-24) -24 t9 -14.4 agelicatin V a l4.4 24 O.6