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(a) Given a 44.0 V battery and 22.00 and 88.00 resistors, find the current in A) and power in W) for each when connected in s

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Solna 2252 882 I I 1 I {= 441 Now, Current . It E 22788 44 22789 -> I= 0.4 A So, 122= I= 188= 0.4A Ans Now, Pe= I*22 = (0.4)*

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