If a 5 kg box is on an inclined surface and moved 5 m by a...

Question

Question

If a 5 kg box is on an inclined surface and moved 5 m by a 10 N forces showed in the figure. Find the work done by the force.

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Answer 1

Answer #1

Work done by force F, Wf = F * d * cos(α)

F = 10 N

d = 5 m

α = 20 deg

Wf = 10 N * 5 m * cos(20)

Wf = 46.98 Joules

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Answer 2

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