Answer) AB, Ab, aB and ab.
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Explanation: The genotype is AaBb. When the genes are unliked, then there are not found crossing over between two genes. The number of gametes= {2}^n = (2)^2 = 4
Here n is the number of heterozygous genes. There are two genes i.e. A and B.
Number of gametes are: AB, Ab, aB and ab.
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Answer] 'c' is the answer.
miRNA stands for micro RNA. This is an inhibitory mRNA. It binds to the complementary sequence in target mRNA. This leads to silence the mRNA. This is the case of post transcriptional regulation.
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Answer} a is the answer.
The heterochromatin is the tightky packed region. The transcription factor can not interact with promoter. That's why the transcription is not found. ( heterochromatin,not transcribed)
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Answer} e is the answer.
Methylation occurs on the Adenine and Cytosine nitrogenous bases. Hence there are not found methylation on all four bases.
It is a transcriptional mode of regulation.
It leads to slience the gene in the region of methylation. It leads to imprint the genes.
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Answer) b is the answer.
Retroviruses have reverse transcriptase enzyme. It leads to synthesise RNA from DNA.
If the two genes are unlinked, an organism with the genotype of AaBb can produce gametes...