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Problem 1: C = 2 nF C = 4nF For the circuit shown in the figure, find the equivalent capacitance between a and b. Cs = 5 nF S
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Answer #1

G=ant Cy=Yuf We know Resultant Capacitor G=5uf Sola for- (i) Series CG= Ca Co Cat ci) Pascallef => Gp = =) p = Cat G alt b ArNw, Gay & G au imparable C36211 = Gore + C 2.4.1 Sint a ult Inf Thb Inf Now, equivalent resultand Ces = 5x3 5+ 3 ک/ 8 1.875 n

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