Question

For the circuit shown below, what is the value of current lī? IS I, ΠΙ, 20 Ω 50230° V Η -j50 Ω j30 Ω Ο 1.39A2-26.310 Ο 1Α2-1200 Ο 1A1200 Ο 0.72A26.31

Answer 1

Solution :- Griven circuit is - IS Let 21 = (20+150) Itt I 2 zon Z2 = (-j5on) 50230 (nt v Z -json) ₂ j300 Here as the current Iz flows through the impedance <1 and the voltage source of 50230V is connected in parallel with both the boy anches, so current 50 % 30 I1 = 50 230 (20+j30) Amp. ZI Note - If any impedance, FZ in rectangle form is given as z=arib then in polar form it is written 2 = JQ2+62. Ztan' ) = con as as 11 = (20+130)n, so in polar form 21 = |(20)2+(302) <ten' (30) = 36.01 (56.312 so , current 502309 Il a (20+130) = 50.230 36.01 256.31 Il = 1.39 <-26.31 Amp. Thus, the value of current I, is 1.392-26.51 Amp. so option ist is correct.