Question

For questions 1 through 6, use the graph shown, which shows the concentration of a substance, in parts per million (ppm), as a function of time, in days. 7 3 2 1 0 0 14 16 18 20 2 4 6 8 12 10 Time (days) 1. What is the concentration on day 6? (a) 2.5 ppm (b) 4 ppm (c) 5.5 ppm (d) 7 ppm 2. What is the rate of change? 1 (b) à ppm per day ppm per day (c) Í ppm per day ppm per 5 day 3. How much does the concentration rise over the duration of 3 days? (a) 0.5 ppm (b) ppm (c) 2 ppm (d) 2.5 ppm 4. Find the initial value of the concentration. (a) 3 ppm (b) 4.5 ppm (c) 6.5 ppm (d) 8 ppm 5. Which is an equation representing concentration, c, as a function of time, t? (a) c=8- (b) c=6-5 e) c=sthan (d) c=3" 6. Use the equation to predict the concentration on day 18. (a) O ppm (b) 3.5 ppm (c) 6 ppm (d) 7.5 ppm

Answer 1

Que. Solution - Griver graph is y-axin 7 6 Concentration (ppm) 3 2. x-axis 2 -5-240 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Time (days)

is 4 ppm. の l. from the given graph concentration at day 6 ie. option (6) Бо , rate is correct. 2. Since graph of concentration of a substance with respect to time is linear Change in concentration change in time graph, change in concentration = in time = of change 6-3=3 I from and change rate of change 3 I ppm /day 18 . 6 is 3. 6 days is . option (6) is correct Since graph is linear and concentration sine over is rise in concentration over 3 days = ² = 0.5ppm :: obtion (9) correct. 4. from given graph initial value of the concentration is concentration at t zo which is 3 bbm i option (9) is correct. 5. Since graph is linear passing throough (0,3) and (6,4) then equation of graph representing concentration ( CI as a function of time it) will be an follows, 4-3 C -3 (t-o) 6-o C-3 1 t 6

C = 3 + It 6 so is correct. 6. Equation option (d) repoesenting relation between C and t is 2 3 t It 6 then for day 18 ie. t =18 с 3 td 6 X с = 6 bom .. optien (C) is correct.