Question

Given the following data and network, find answer the questions 18-20 if you're asked to finish this project 2 days earlier than its normal duration. Indirect cost (overhead) is $200 per day. 9.12 E 1.8 اليا 12.19 10.13 B 7 H 7 1.8 13, 20 0.1 1.7 8.15 20,25 15, 20 F А I K с 7 5 1 8.15 0.1 15.20 20,25 2.8 1.4 4. 12 15. 18 D 3 6,9 G 8 J 3 9.17 17, 20 Activity Duration Normal Crash Days Shortened 1 А B С D E F G H 1 J K 7 6 3 3 7 8 1 Cost Duration Cost Crash Cost Normal Crash Difference Difference per Day 1 $8001 $800 4 $1,000 $1,600 4 $300 $500 2 $400 $800 $1001 $200 5 $500 $800 4 $1,200 $1,400 6 $350 $600 3 $700 $850 2 $500 $1,000 4 $450 $800 Days Cut Project Duration Increased cost Direct Cost Overhead Cost Total Cost 5 3 5

what is the normal cost of this project?

what is the cost of the project after 2 days shortening?

what is the crashing cost per day for avtivity G?

Answer 1

Solue- 9,12 1,8 B 12,19 th 7 15.20 20,25 0.1. 8.15 1,7 CA Ik. XI if 8,15 5 Acer of In this network we can see that critical path is A - B -f-I-K. (9) nornal cost project $ 6300 +200x25) $11300 I cost of project after after 2 days Shortening will be done along couitical path cost llope of ka of a mashing $350 (day. $75 1 day 150 s 2 cost slope cost stope of Good = $ 150/day cost slope of B = Bec = $ 800/day we can see that Slope is of I activity and its A days. So In this Minincune cost ceashing Potential is 2

Total cost = 80 reashing activity I by 2 days. Cost of I activity becomee = $850 Noul. Sunning cost of all activities + indiget Direct cost & indirect cost 6450 + (23x 200) 6450 + 4600 = after clashing I by 2 day all have now he two critical patha ci) A-B-F-I-K. A-B-E-H-K, $ 11050 (ii for activity re of cost Ci is a cuashing per day Copa ceeash cost - nomial cost cost slope nornal tine crash time cs is of can 1400 - 1200 200 8-4 4 of cel = $ 50 1 day: