Question

06) The B-oxidation of saturated fatty acids, is a series of four reactions. Assume that you have the Lauric acid with 12 carbons. (15 points) A) Write the 4 reactions that involved in each B-oxidation of the fatty acid. You need to show the structure and general names of the reactants and products, name of enzymes and the all input and output molecules in each reaction. You can use R to represent the not reacted carbons) (10 points) B) Calculate the total number of ATP molecules that will be released after complete B-oxidation reactions for the Lauric acid. (you need to show all your calculation steps and all the molecules that you used for this calculation) (5 points)

Answer 1

B- onidation of lauric Acid. Laurive acid. (CH2) vc CH3 cooh B- onidation H H OH Ć- + CH₂ (CH2) = H H COA-SH STEP O АТР → AMP + Pi -s-con 8 - HC- CH₂ largic acull 8-5 STEP 1 COA CH₃ (CH₂); KEA CECH--5-COA FADH₂ CH3 (CM₂) 8 - HC Trans-2-enoyl HO COA STEP 2 po ll C C-s-CoA 3-4-hydroxy acyl Olt STEP 3 CH₂ (CH2), -HG- -HC - CH₂ KDH+ CH₃ (CH2) 8 - C- CH₂ - C-S-COA NADI NADH + H7 COA B- ketoacyl.com

HSCOA Bree to thical CH₃ (CH2) e STEP 4 Ć - Scon st a С 8 -SEOA + CH₃ Capsic acylcoa Acetyl Co A

The STEP 1, 2, 3, 4 are repeated for 4 times, total cycles are 5 for oxidation of lauric acid.

STEP 1 reaction is Oxidation by Acyl Co A dehydrogenase

STEP 2 reaction is Hydration by enoyl Co A dehydrogenase

STEP 3 reaction is Oxidation by L- beta hydroxyl acyl CoA

STEP 4 reaction is Thiolation by Thiolase

Total number fatty acids produced after complete oxidation of Lauric acid is

5 FADH = 10 ATP

5 NADH = 10 ATP

6 acetyl Co A = 72 ATP

Total = 92

2 ATP are lossed for activation for lauryl Co A

So Total ATP produced are 92 - 2 = 90

Total 90 ATP are produced for complete oxidation of 12 carbon fatty acid ( Lauric acid)