Question

can someone help me with this problem?

Using either regular functions or singularity functions determine the deflection at point C of the below beam.

Forces on the beam:

F1= 6 (k), F2 = 8 (k), F3 = 4 (k)

The reactions for the beam are:

R(A) = 10.08695652173913 (k), R(E) = 7.913043478260869 (k)

Assume: E = 29000 ksi and I = 750 in⁴

Show all work. Equations for shear, moment, slope of the elastic curve and deflection must be shown. Show your answer for the

deflection at C on the work.

To submit work for this problem type in the value of force F1 ______

Fik F2k Fz k A B С D E 5 ft. 5 ft. 8 ft. 5 ft.

Answer 1

6k BK 4K 2 (x=0) san I 15 B5 Ev=o7 RARE = 18k "RE EM$=0> RA123 -6(13) +2(13) +4(5) REF RA= 232 23 < 182 23 ocx55 3. Fx-x = RA= 232 23 8.Mxx - Rala) - 2338) sexe 10' 8. Fx.x = 23 22 -6 = 9 B. Mx-* = 232(1) -6(-5 94 23 94x+ 30 23

10'54 € 18': SFx-x 94 - 8 = 23 -90 23 B. Mx-x= 94x+30 - 8 (2-10) - 2.0 (x) + 110 18 2 x 4 23't 3-fx-x--00 -4 = -123 -90) + 110 - 4(2-18) = -582 () + 182 B.MX-X 23 23 EI = 29x10² x 750k- 29x10² x 750 K-(ft)? EI o ex-5 23 24 23 (EI = 151041.667 kfft)? By double integration method, Elly") - M 5'<a 10' 10'21518' 18'47 23' EI/y") - -(2-5)-3(1-10) -4(2-18) Integrating, E1 (g) = Es(0) = 297 +6, 1-3(x+5)*) -4(2-10) -2(+18) Internating, -4 (2-10), 3(x+18) 3 ET(Y) = 55(0) 2324? -(2-5) 138 + CD +62 End Conditions, @x=0 8=0 19 x=23 d=0 232 (23)+ 234, -(e)? (3) - 3 (s) - 0 138 -11610 23

at x= 10' (c) EI(6)- 23260) 11610 19(10) - (10-5)3 (151041.667) (dc = -0.0231 feet de = -0,2774 in - 3491.667