choice c is incorrect. could someone help me solve this and
explain how?Solution:
Given that
confidence level = c = 90% = 0.90
sample size = n = 53
Since the population standard deviation is unknown , we use t distribution.
(when it is known , we use z distribution)
c = 0.90
= 1- c = 1- 0.90 = 0.10
/2
= 0.10
2 = 0.05
Also, d.f = n - 1 = 53 - 1 = 52
=
=
0.05,52
= 1.674689 = 1.67
(use t table or t value calculator)
Answer is
A.
= 1.67
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