Using Hess's Law, calculate ΔH°R
Equation: B2H6 (g) + 6 Cl2 (g) --> 2BCl3 (g) + 6 HCl (g)
Given these 3 equations: (please show all work)
BCl3 (g) + 3H2O (l) --> H3BO3 (g) + 3HCl (g) (ΔH°R = -112.5 KJ/mol BCl3)
B2H6 (g) + 6H2O (l) --> 2H3BO3 (g) + 6H2 (g) (ΔH°R = -493.4 KJ/mol B2H6)
H2 (g) + Cl2 (g) --> 2HCl (g) (ΔH°R = -184.6 KJ/mol H2)
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Using Hess's Law, calculate ΔH°R Equation: B2H6 (g) + 6 Cl2 (g) --> 2BCl3 (g) +...
calculate Δh0
ulate AHo (in kJ/mol) for the reaction: B2H6(g)+6 Cl2(g)2 BCls(g)+6 HCl(g) ven the following data: BCI5(g)+3 H2O(I) H3BO:(g)+3 HCl(g) AH° = -112.5 kJ/mol B2H&(g) + 6 H2O(1) 2 H3BO:(g) + 6 H2(g)AH°= -493.4 kJ/mol AHOC(HCI, g) -92.3 kJ/mol
Consider the following thermal equations: 2B (s) + 3H2(g) ⟶ B2H6 (g) ΔH = +36kJ/mol 2B (s) + 3/2O2 (g) ⟶ B2O3 (s) ΔH = −1273 kJ/mol H2 (g) + 1/2O2 (g) ⟶ H2O (l) ΔH = −286 kJ/mol H2O (l) ⟶ H2O (g) ΔH = +44 kJ/mol Calculate ΔH for the combustion of borane, B2H6 (g) + 3O2 (g) ⟶ B2O3 (s) + 3H2O (g)
I found the Delta H rxn to be -1376 KJ .
I'm confused on the steps to find my limiting reactant and grams of
BCl3.
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solution pls
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