Hess's Law
Given the following data:
P(s) + 3/2H2(g) → PH3(g) ΔH°= +5.0
kJ
PH3(g) + 2O2(g) →
H3PO4(l) ΔH°= -1272.0 kJ
2P(s) + 5/2O2(g) → P2O5(s)
ΔH°= -1492.0 kJ
H2(g) + 1/2O2(g) → H2O(l) ΔH°=
-286.0 kJ
calculate ΔH° for the reaction:
H3PO4(l) → 1/2P2O5(s) +
3/2H2O(l)
ΔH°=??
also please explain how you found the answer
Hess's Law Given the following data: P(s) + 3/2H2(g) → PH3(g) ΔH°= +5.0 kJ PH3(g) +...
4CO(g) + 8H2(g) -----> 3CH4(g) + CO2(g) + 2H2O(l) Use the following data as needed to determine ΔH for this reaction. 1.) C(s) + 1/2O2(g) -----> CO(g) ΔH = -110.54 kJ 2.) CO(g) + 1/2O2(g) -----> CO2(g) ΔH = -282.97 kJ 3.) H2(g) + 1/2O2(g) -----> H2O(l) ΔH = -285.85 kJ 4.) C(s) + 2H2(g) -----> CH4(g) ΔH = -74.85 kJ
4CO(g) + 8H2(g) -----> 3CH4(g) + CO2(g) + 2H2O(l) Use the following data as needed to determine ΔH for this reaction. 1.) C(s) + 1/2O2(g) -----> CO(g) ΔH = -110.54 kJ 2.) CO(g) + 1/2O2(g) -----> CO2(g) ΔH = -282.97 kJ 3.) H2(g) + 1/2O2(g) -----> H2O(l) ΔH = -285.85 kJ 4.) C(s) + 2H2(g) -----> CH4(g) ΔH = -74.85 kJ
2. Given the following data: H2O(l) → H2(g) + 1/2O2(g) ΔH° = 285.8 kJ 2HNO3(l) → N2O5(g) + H2O(l) ΔH° = 76.6 kJ 2N2(g) + 5O2(g) → 2N2O5(g) ΔH° = 28.4 kJ Calculate ΔH° for the reaction: 1/2N2(g) + 3/2O2(g) + 1/2H2(g) → HNO3(l) Note that you should be able to answer this one without needing to use any additional information from the thermo table. I've attempted this question multiple times. I am able to get to the simplified eqaution...
Consider the following data. 2 H2(g) + O2(g) 2 H2O(l) ΔH = -571.7 kJ N2O5(g) + H2O(l) 2 HNO3(l) ΔH = -92.0 kJ N2(g) + 3 O2(g) + H2(g) 2 HNO3O(l) ΔH = -348.2 kJ Use Hess's law to calculate ΔH for the reaction below. 2 N2O5(g) 2 N2(g) + 5 O2(g) ΔH = _____kJ
12. Use Hess's Law to find AH for this reaction. (5) NO2(g) +2H2(g) ---> 2H2O(e) + NHs(g) Given the following two equations: 2NH3(g) -->N2(g) + 3H2(g) AHo +92 kJ 2N2(g)+ 2H2O(l) ---> NO2(g) + 2H2(g) AH° = +170 kJ
Given the following data: 2C2H2(g) + 5O2(g) → 4CO2(g) + 2H2O(l) ΔH = -2600 kJ C2H2(g) + 2H2(g) → C2H6(g) ΔH = -312 kJ 2H2(g) + O2(g) → 2H2O(l) ΔH = -572 kJ Find the ΔH of the following reaction: 4CO2(g) + 6H2O(l) → 2C2H6(g) + 7O2(g)
Hess's Law (b) Given the following thermochemical data: 2HNO3(aq) +A920(s) - H2O(1) +2AgNO3(aq) AH = -44.8 kJ Ag20(s) - 2Ag(s) + 1/2O2(9) AH = 31.0 kj H20(1) - H2(9)+1/202(9) AH = 285.8 kJ Use Hess's Law to determine AH for the reaction: Ag(s)+HNO3(aq) → 12H2(9)+AgNO3(aq) AH =
Consider the following thermal equations: 2B (s) + 3H2(g) ⟶ B2H6 (g) ΔH = +36kJ/mol 2B (s) + 3/2O2 (g) ⟶ B2O3 (s) ΔH = −1273 kJ/mol H2 (g) + 1/2O2 (g) ⟶ H2O (l) ΔH = −286 kJ/mol H2O (l) ⟶ H2O (g) ΔH = +44 kJ/mol Calculate ΔH for the combustion of borane, B2H6 (g) + 3O2 (g) ⟶ B2O3 (s) + 3H2O (g)
Using Hess's Law, calculate ΔH°R Equation: B2H6 (g) + 6 Cl2 (g) --> 2BCl3 (g) + 6 HCl (g) Given these 3 equations: (please show all work) BCl3 (g) + 3H2O (l) --> H3BO3 (g) + 3HCl (g) (ΔH°R = -112.5 KJ/mol BCl3) B2H6 (g) + 6H2O (l) --> 2H3BO3 (g) + 6H2 (g) (ΔH°R = -493.4 KJ/mol B2H6) H2 (g) + Cl2 (g) --> 2HCl (g) (ΔH°R = -184.6 KJ/mol H2)
For the following reaction: 2Na(s) + 2H2O(l) → 2NaOH(s) + H2(g) Compound ΔH°f (kJ mol-1) S° (J mol-1 K-1) Na (s) 0.00 51.30 H2O (l) -285.83 69.91 NaOH (s) -425.93 64.46 H2 (g) 0.00 130.68 Calculate ΔG°rx (in kJ) at 391.96 K for this reaction. Assume ΔH°f and S° do not vary as a function of temperature.