Question

= What is the specific heat of an unknown metal (mass 2.30 g) if its temperature increased from 15.0 °C to 31.0 °C when absorbing 14.168 J of heat? Round to three significant figures. Provide your answer below: J g°C

Answer 1

The formula used is:

(Thermal change (J)) = (mass (g)) (specific heat (J / g°C)) (final temperature-initial temperature, in °C)

Here :

Thermal change = + 14.168 J (The + sign means heat is absorbed. For the released heat, the sign of thermal change is'-')

Mass = 2.30 g

Final temperature = 31.0°C

Initial temperature = 15.0°C

So, put the value:

(+ 14.168 J) = (2.30 g) (specific heat) (31.0°C-15.0°C)

Solve, the specific heat of the metal = 0.385 J / (g°C)